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Rus_ich [418]
3 years ago
13

Solve this equation -4(y-2)=12

Mathematics
2 answers:
love history [14]3 years ago
7 0

Answer: y= -1

Step-by-step explanation:

MakcuM [25]3 years ago
4 0

Answer: y= -1

Step-by-step explanation: multiply -4 with y and -2, you get -4y and 8 =12

Subtract 8 on both sides

-4y=4

Divide 4 both sides

y=-1

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LMNP is a rectangle. Find the value of x and the length of each diagonal. LN=6x+9and MP=9x−6
Alexus [3.1K]

Answer:

see explanation

Step-by-step explanation:

The diagonals of a rectangle are congruent, thus

MP = LN , substitute values

9x - 6 = 6x + 9 ( subtract 6x from both sides )

3x - 6 = 9 ( add 6 to both sides )

3x = 15 ( divide both sides by 3 )

x = 5

Thus

MP = 9(5) - 6 = 45 - 6 = 39 and LN = 6(5) + 9 = 30 + 9 = 39

6 0
4 years ago
What's a verbal expression
Nastasia [14]
A mathematical statement that is expressed in words
7 0
2 years ago
Factor x3 + 2x2 + x completely.<br><br> a. (x+1)^2<br><br> b. x(x+1)^2<br><br> c. x(x+1)^2
enot [183]

Option B

<u>ANSWER:  </u>

The factors of  $x^{3}+2 x^{2}+x$ is $x(x+1)^{2}$

<u>SOLUTION: </u>

Given, cubic expression is  $x^{3}+2 x^{2}+x$

Now, we have to find the factors of above equation.

To factorize the given equation, follow the below steps:

$\mathrm{x}^{3}+2 \mathrm{x}^{2}+\mathrm{x}$

Since x is common in every term of expression, we can take it as common

$x\left(x^{2}+2 x+1\right)$

“2x” can be rewritten as “x + x”, the above equation becomes,

$x\left(x^{2}+x+x+1\right)$

Taking the common terms out of bracket. we get

x(x (x + 1) + 1 (x + 1))  

Taking (x + 1) as common., we get

x ((x + 1)(x + 1))  

$x(x+1)^{2}$

Hence, the second option b is correct.

7 0
4 years ago
Help! I will give brainilest to correct answer UwU
sattari [20]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

Here's the solution :

  • 1 \dfrac{1}{2}

  • \dfrac{3}{2}

  • 1.5

therefore , correct choice is B

7 0
3 years ago
Read 2 more answers
Bastien, Inc. has been manufacturing small automobiles that have averaged 50 miles per gallon of gasoline in highway driving. Th
alexira [117]

Answer:

We conclude that the the manufacturer's advertising campaign is not correct.

P-value of test = 0.067.

Step-by-step explanation:

We are given that an independent testing service road-tested 36 of the automobiles. The sample showed an average of 51.5 miles per gallon. The population standard deviation is 6 miles per gallon.

We have to conduct a test to determine whether or not the manufacturer's advertising campaign is legitimate.

<u><em>Let </em></u>\mu<u><em> = population average gasoline of new small cars in highway driving.</em></u>

SO, <u>Null Hypothesis</u>, H_0 : \mu \leq 50 miles per gallon   {means that the manufacturer's advertising campaign is not correct}

<u>Alternate Hypothesis</u>, H_A : \mu > 50 miles per gallon   {means that the manufacturer's advertising campaign is correct}

The test statistics that will be used here is <u>One-sample z test</u> <u>statistics</u> as we know about the population standard deviation;

                         T.S.  = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where,  \bar X = sample average gasoline = 51.5 miles per gallon

              \sigma = population standard deviation = 6 miles per gallon

              n = sample of automobiles = 36

So, <em><u>test statistics</u></em>  =   \frac{51.5-50}{\frac{6}{\sqrt{36} } }

                               =  1.50

<em>Now at 0.05 significance level, the z table gives critical value of 1.6449 for right-tailed test. Since our test statistics is less than the critical values of z as 1.50 < 1.6449, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.</em>

<u>Also, P-value is given by the following formula;</u>

         P-value = P(Z > 1.50) = 1 - P(Z \leq 1.50)

                                            = 1 - 0.93319 = <u>0.067 or 6.7%</u>

Therefore, we conclude that the the manufacturer's advertising campaign is not correct as its new small cars average less than or equal to 50 miles per gallon in highway driving.

3 0
4 years ago
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