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Evgen [1.6K]
4 years ago
7

In a test strength at a carnival, a hammer drives a metal weight up a rod to ring a bell at the top. If the bell is 24 ft above

the starting position of the weight, what is the minimum initial vertical velocity needed to ring the bell?

Physics
1 answer:
vladimir2022 [97]4 years ago
6 0

Answer:

39 ft/s

Explanation:

Given:

Δy = 24 ft

v = 0 ft/s

a = -32 ft/s²

Find: v₀

v² = v₀² + 2aΔy

(0 ft/s)² = v₀² + 2 (-32 ft/s²) (24 ft)

v₀ ≈ 39 ft/s

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Answer:

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Explanation:

Given,

The initial velocity of the car, u = 30 m/s

The height of the cliff, h = 50 m

Let the car drives off the cliff with a horizontal velocity of 30 m/s.

The formula for a projectile that is projected from a height h from the ground is given by the relation

                                R_{max}= \frac{u}{g}\sqrt{u^{2} + 2gh }  m

Where,

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Substituting the values in the above equation

                   R_{max}= \frac{30}{9.8}\sqrt{30^{2} + 2X9.8X50 }  

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