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Evgen [1.6K]
3 years ago
7

In a test strength at a carnival, a hammer drives a metal weight up a rod to ring a bell at the top. If the bell is 24 ft above

the starting position of the weight, what is the minimum initial vertical velocity needed to ring the bell?

Physics
1 answer:
vladimir2022 [97]3 years ago
6 0

Answer:

39 ft/s

Explanation:

Given:

Δy = 24 ft

v = 0 ft/s

a = -32 ft/s²

Find: v₀

v² = v₀² + 2aΔy

(0 ft/s)² = v₀² + 2 (-32 ft/s²) (24 ft)

v₀ ≈ 39 ft/s

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A 65-kg person stands on a scale in a moving elevator while holding a 5.0 kg mass suspended from a massless spring with spring c
disa [49]

Answer:

The question is incomplete. However, I believe, it is asking for the acceleration of the elevator. This is 3.16 m/s².

Explanation:

By Hooke's law, F = ke

F is the force on a spring, k is the spring constant and e is the extension or compression.

From the question,

F = (1.08\text{ kN/m}) \times (6.0 \times 10^{-2}\text{ m}) = 64.8 \text{ N}

This is the force on the mass suspended on the spring. Its acceleration, a, is given by

F = ma

a = \dfrac{F}{m}

a = \dfrac{64.8 \text{ N}}{5\text{ kg}} = 12.96\text{ m/s}^2

This acceleration is more than the acceleration due to gravity, g = 9.8 m/s². Hence the elevator must be moving up with an acceleration of

12.96 - 9.8 m/s² = 3.16 m/s²

7 0
3 years ago
the brightness of stars as they appear from earth is measured by _______ magnitude. a. light b. apparent c. relative d. absolute
xxTIMURxx [149]
How bright a star appears from Earth is the star's apparent magnitude.
8 0
3 years ago
Please choose the answer that describes the scientific notation for 5,098,000. 
galben [10]
D. 5.098 x 106 is the correct answer when reduced to the proper notation.
3 0
3 years ago
As part of a NASA experiment, golfer Tiger Woods drives a golf ball on the moon, where g = 1.60 m/s2. He launches a golf ball wi
Elanso [62]

Answer:

Horizontal distance, R = vo2 sin(2x45)/g

v = 285 km/h = 79.17 m/s

R = 79.172 x 1/1.6

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8 0
3 years ago
Would anyone be kind enough to help me? :)
Travka [436]

Answer:

The racetrack is 996.7 meters long

Explanation:

Convert 251km/h to km/s (kilometers per second)

3600 seconds in an hour, so:

251/3600 = 0.0697km/s

Convert km/s to m/s (meters per second)

1000 meters in a kilometer, so:

0.0697*1000 = 69.7m/s

Find length of racetrack:

69.7m/s*14.3s = 996.7m

If the racer travels 69.7 meters in one second and it takes 14.3 seconds to complete a lap, the racetrack is 996.7 meters long.

6 0
3 years ago
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