While taking off from an aircraft carrier, a jet starting from rest accelerates uniformly to a final speed of 40. meters per sec

Question

2 years ago

12

ond on a runway that is 70. meters long. What is the magnitude of the acceleration of the jet? Group of answer choices

1 answer:

mariarad [96] · Answer 1 · 2022-06-27T21:25:58+03:00

The acceleration of the jet is $11.4 m/s^2$

Explanation:

Since the jet motion is a uniformly accelerated motion (=constant acceleration), we can use the following suvat equation:

$v^2-u^2=2as$

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement

For the jet in this problem, we have

u = 0 (it starts from rest)

v = 40 m/s (final velocity)

s = 70 m (length of the runway)

Solving for a, we find the acceleration:

$a=\frac{v-u}{t}=\frac{40^2-0}{2(70)}=11.4 m/s^2$

Learn more about acceleration:

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