While taking off from an aircraft carrier, a jet starting from rest accelerates uniformly to a final speed of 40. meters per sec
1 answer:
The acceleration of the jet is
Explanation:
Since the jet motion is a uniformly accelerated motion (=constant acceleration), we can use the following suvat equation:
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the displacement
For the jet in this problem, we have
u = 0 (it starts from rest)
v = 40 m/s (final velocity)
s = 70 m (length of the runway)
Solving for a, we find the acceleration:
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Answer:
0.88752 kgm²
0.02236 Nm
Explanation:
m = Mass of ball = 1.2 kg
L = Length of rod = 0.86 m
= Angle = 90°
Rotational inertia is given by
The rotational inertia is 0.88752 kgm²
Torque is given by
The torque is 0.02236 Nm
The thermal efficiency of an engine is
where
W is the work done by the engine
Q is the heat absorbed by the engine to do the work
In this problem, the work done by the engine is W=200 J, while the heat exhausted is Q=600 J, so the efficiency of the machine is
where
W is the work done by the engine
Q is the heat absorbed by the engine to do the work
In this problem, the work done by the engine is W=200 J, while the heat exhausted is Q=600 J, so the efficiency of the machine is