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kati45 [8]
3 years ago
11

The mass of Venus is 81.5% that of the earth, and its radius is 94.9% that of the earth. If a rock weighs 75.0 N on earth, compu

te the acceleration due to gravity on the surface of Venus in comparison to the earth's gravitational acceleration
Physics
1 answer:
IgorLugansk [536]3 years ago
7 0

Answer:

g = 0.905 gE

W  = 67.9 N

Explanation:

given data

mass of Venus mv =  81.5% = 0.815

radius Rv = 94.9% = 0.949

weighs W = 75.0 N

solution

we apply here acceleration due to gravity at earth surface that is

g = \frac{Gm}{R^2}   = 9.80 m/s²  ............1

so

g = \frac{G(0.815)}{0.949R^2}  

g = 0.905 gE

and

W = m gv

W = 0.905 m gE

W  = 0.905 × 75

W  = 67.9 N

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Answer: 6.36

Explanation:

Given

Radius of grindstone, r = 4 m

Initial angular speed of grindstone, w(i) = 8 rad/s

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Time used, t = 4 s

Angular acceleration of the grinder,

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Number of complete revolution in 4s =

Δθ = w(i).t + 1/2.α.t²

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Δθ = 32 + 1/2 * 16

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Therefore, the grindstone does 6.36 revolutions during the 4 s interval

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A psychologist is interested in exploring the effect tutorial support on students academic performance and assign students in to
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Answer:

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The experimental group receive the treatment while the control group do not receive the treatment. The independent variable is manipulated and its impact on the dependent variable is evaluated.

The control group are students who did not receive the tutorial support while the experimental group are students that received the tutorial support.

The dependent variable in this case is academic performance. Its outcome depends on the presence or absence of tutorial support (independent variable).

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Answer:

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Explanation:

2

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