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3 years ago

I need help understanding this concept . Would appreciate it so much. Thank you

Physics

1 answer:

Firlakuza [10]3 years ago

7 0

Answer:

Explanation:

Both these questions are based on the Universal Law of Gravitation, which is given by :

F = Gm1m2 / r²

2) F = 6.67 x 10⁻¹¹ x 8 x 10³ x 1.5 x 10³ / 1.5 x 1.5

F = 6.67 x 10⁻⁵ x 8 / 1.5

F = 35.57 x 10⁻⁵ N

3) F = 6.67 x 10⁻¹¹ x 7.5 x 10⁵ x 9.2 x 10⁷ / 7.29 x 10⁴

F = 6.67 x 10⁻³ x 7.5 x 9.2 / 7.29

F = 63.13 x 10⁻³ N

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8.Which set of coefficients would

Viefleur [7K]

Answer:

The set of coefficients that would correctly balanced the equation

NaCl → Na + Cl2 is the option D

(2,2,1)

Explanation:

In this reaction sodium chloride splits into sodium and chlorine.

For balancing the equation we should have number of atom of the element in the left hand side equal to the number of atom of the same element in the right-hand side.

so here in left hand side only one sodium and one chlorine is given and in the right-hand side one sodium and two chlorine is given.

So for the balancing the equation both the side should be same.

So we will write the balanced equation as

2NaCl → 2Na + Cl2

So, right now it is balanced that is two sodium and two chlorine on the left hand side as well as the right hand side.

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3 years ago

As a dilligent physics student, you carry out physics experiments at every opportunity. At this opportunity, you carry a 1.11-m-

soldier1979 [14.2K]

Answer:

The strength of the magnetic field is 0.0842 mT

Explanation:

Given:

Velocity of rod $v = 3.07$ $\frac{m}{s}$

Length of rod $l = 1.11$ m

Induced emf across the rod $\epsilon = 0.287 \times 10^{-3}$ V

According to the faraday's law

We have a special case for moving rod in magnetic field.

Induced emf in moving rod is given by,

$\epsilon = Blv$

Where $B =$ strength of magnetic field

$B = \frac{\epsilon}{lv}$

$B = \frac{0.287 \times 10^{-3} }{3.07 \times 1.11}$

$B = 0.0842 \times 10^{-3}$ T

$B = 0.0842$ mT

Therefore, the strength of the magnetic field is 0.0842 mT

7 0

3 years ago

A box with the mass of 20 kg at 5 m is lifted to 20 m. How much work was 7 points<br> done?

kirza4 [7]

Answer:

$2,900\: \mathrm{J}$

Explanation:

Work is given by the equation $W=F\Delta x$ where $F$ is force and $\Delta x$ is displacement.

Displacement is defined as change in position. In this case, the box moves from 5m to 20m. Its displacement is $20-5=15\:\mathrm{m}$ .

The force acting on the box is the force of gravity, given as $F_g=mg$ .

Therefore, the total work done is:

$W=F\Delta x=mg\Delta x = 20\cdot 9.81\cdot 15=2,943=\fbox{$2,900\:\mathrm{J}$}$ (two significant figures).

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