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Ratling [72]
4 years ago
14

How many atoms are in 36 mol Na?

Chemistry
1 answer:
Basile [38]4 years ago
4 0
To determine the number of atoms present in the given number of moles of sodium which has a chemical formula of Na, we multiply the number by the Avogadro's number, 6.022 x 10^23. That is,
                              number of atoms = (36 mol) x (6.022 x 10^23) 
                                                          = 2.16792 x 10^25 atoms of Na
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Which diagram shows electrons violating the Pauli exclusion principle?
Neporo4naja [7]
Correct Answer: Option C

Reason:
<span>The </span>Pauli Exclusion Principle<span> states as '<em>in an atom or molecule, no two electrons can have the same four electronic quantum numbers. Further, an orbital can contain a maximum of only two electrons, the two electrons must have opposing spins.</em>'
</span>
Thus, it can be seen that in option C, electrons in last 2 subshell have electrons with same spin, which is a violation of Pauli Exclusion Principle .
7 0
3 years ago
The concentration of a biomolecule inside a rod-shaped prokaryotic cell is 0.0029 m. calculate the number of molecules inside th
bagirrra123 [75]
Molarity is expressed as:
Molarity = moles / liter

Given that the cell is rod-shaped, its volume is calculated using the formula for a cylinder's volume:

V = πr²L
V = π * (0.6)² * 4.9
V = 5.54 μm³

1 Liter = 10³ mm³
1 mm = 10³ μm
1 mm³ = 10⁹ μm³
1 liter = 10¹² μm³

So the volume in liters is:
5.54 x 10⁻¹² L

Moles = molarity * liters
Moles = 0.0029 * 5.54 x 10⁻¹²
Moles = 1.61 x 10⁻¹⁴

To get the number of molecules, we multiply the moles by Avagadro's number

Number of molecules = 1.61 x 10⁻¹⁴ * 6.02 x 10²³

There are 9.69 x 10⁹ molecules in the cell
4 0
3 years ago
In a combustion reaction, one of the reactants is always _______________.
QveST [7]
In a combustion reaction, one of the reactants is always oxygen.
4 0
4 years ago
Read 2 more answers
A certain substance X has a normal freezing point of -6.4 C and a molal freezing point depression constant Kf= 3.96 degrees C.kg
Brut [27]

Answer:  1.0\times 10^2g

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=T_f^0-T_f=(-6.4-(13.6))^0C=7.2^0C = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte like urea)

K_f = freezing point constant = 3.96^0C/m

m= molality

\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}}\times \text{weight of solvent in kg}}

Weight of solvent (X)= 950 g = 0.95 kg  

Molar mass of non electrolyte (urea) = 60.06 g/mol

Mass of non electrolyte (urea) added = ?

7.2=1\times 3.96\times \frac{xg}{60.06 g/mol\times 0.95kg}

x=1.0\times 10^2g

Thus 1.0\times 10^2g urea was dissolved.

8 0
4 years ago
Which element is most plentiful in Earth's crust?
dem82 [27]

Answer:

Oxygen is the most contain in earth but you asked in a,b,c and d. So I'll choice A. aluminium.

5 0
3 years ago
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