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ratelena [41]
4 years ago
6

A solution has a pH of 4.20. Using the relationship between pH and pOH, what is the concentration of OH?? A. 9.9 × 10-1 M B. 6.2

× 10-1 M C. 6.3 × 10-5 M D. 6.7 × 10-6 M E. 1.6 × 10-10M
Chemistry
1 answer:
vivado [14]4 years ago
5 0

The correct answer is option E.

Explanation:

The pH of the solution is defined as negative logarithm of hydrogen ions  concentration in a solution. Mathematically written as:

pH=-\log[H^+]

The pOH of the solution is defined as negative logarithm of hydroxide ions  concentration in a solution. Mathematically written as:

pOH=-\log[OH^-]

The sum of ph and pOH is equal to 14.

pH + pOH = 14

A solution has a pH of 4.20.

pOH=14-pH=14-4.20=9.8

pOH=9.8=-\log[OH^-]

[OH^-]=1.58\times 10^{-10} M\approx 6.0\times 10^{-10} M

Hence, the correct answer is option E.

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Commercial products commonly report concentration in terms of "percentage." Using this
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The answer to the question is 0.8055 as the answer should not include units in it.

Molarity (M) = n/v

n = moles of solute

v = liters of solution

According to question

1% solution → 1 gram of solute for 100 milliliters of solution

2% solution → 2 grams of solute for 100 milliliters of solution

6% NaClO solution → 6 grams of NaClO (solute) for 100 milliliters of solution

Molar mass of NaClO = (22.98 + 35.5 + 16)g/mol = 74.48 g/mol

Atomic mass of Na = 22.98 g/mol

Atomic mass of Cl = 35.5 g/mol

Atomic mass of O = 16 g/mol

1 mol NaClO = 74.48 grams NaClO

74.48 grams NaClO = 1 mol NaClO

6 grams NaClO = (1×6) / 74.48 mole = 0.08055 mole

As unit molarity is mole / liter

So 100 milliliters = 0.1 liters

1 liter = 1000 milliliters

100 milliliters = 100/1000 liters = 0.1 liters

Molarity of NaClO = moles of solute (NaClO) / liters of solution or volume of solution

Molarity of NaClO = 0.08055 / 0.1 mole/L =  0.8055 mole/L

As in question it is mentioned that 'Do not type units into your answer'

So, Molarity of NaClO in clorox bleach = 0.8055

Thus we find out the value of molarity of NaClO in Clorox bleach which came out to be 0.8055 as we dont have to give the answer with units.

Learn more about Molarity here:

brainly.com/question/27208890

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8 0
2 years ago
Which atoms likely to react ? PLS HELPP
Irina18 [472]

Answer:

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Explanation:

8 0
3 years ago
The air pressure for a certain tire is 113 KPa. What is the pressure I’m atmosphere
Fynjy0 [20]

Answer: 1.11 atm

Explanation:

The unit of pressure include kilopascal (kPa), atmospheres (atm), mmHg etc

Now, given that:

Air pressure = 113 KPa

Convert kPa to atm

If 101.325 kPa = 1 atm

113 kPa = Z atm

To get the value of Z, cross multiply

Z atm x 101.325 kPa = 1 atm x 113 kPa

Z = ( 1 atm x 113 kPa) / 101.325 kPa

Z = 1.11 atm

Thus, the pressure is 1.11 atm

7 0
3 years ago
A solution is prepared by combining 5.00 mL of 4.8x10-4 M NaSCN solution, 2.00 mL of 0.21 M Fe(NO3)3 solution and 13.00 mL of 0.
Tcecarenko [31]

Answer:

The analytical concentrations of thiocyanate ions:

[SCN^-]=0.00012 mol/L

The analytical concentrations of ferric ions:

[Fe^{3+}]=0.063 mol/L

Explanation:

Moles (n)=Molarity(M)\times Volume (L)

1) Moles of sodium thiocyanate  = n

Volume of sodium thiocyanate solution = 5.00 mL = 0.005 L

(1 mL = 0.001L)

Molarity of the sodium thiocyanate = 4.8\times 10^{-4} M

n=4.8\times 10^{-4} M\times 0.005 L=2.4\times 10^{-6}mol

1 mole of sodium thiocyanate has 1 mol of thiocyante ions.

So, moles of thioscyanate ions in 2.4\times 10^{-6}mol  of NaSCN.

=1\times 2.4\times 10^{-6}mol=2.4\times 10^{-6}mol

2) Moles of ferric nitrate = n'

Volume of ferric nitrate solution = 2.00 mL = 0.002 L

Molarity of the ferric nitrate = 0.21 M

n'=0.002 M\times 0.21 L=0.00042 mol

1 mole of ferric nitrate has 3 moles of ferric ions.

So number of moles of ferric ions in 0.00042 moles of ferric nitrate is :

3\times 0.00042 mol=0.00126 mol

Volume of nitric acid = 13.00 mL

Total volume by adding all three volumes of solutions = V

V = 5.00 mL + 2.00 mL + 13.00 mL = 20.00 mL = 0.020 L

The analytical concentrations of thiocyanate ions:

[SCN^-]=\frac{2.4\times 10^{-6}mol}{0.020 L}=0.00012 mol/L

The analytical concentrations of ferric ions:

[Fe^{3+}]=\frac{0.00126 mol}{0.020 L}=0.063 mol/L

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