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polet [3.4K]
4 years ago
12

A group of engineers run a trial test on a space probe built for measuring the surface temperature of the sun. After the trial,

the engineers realize that the probe melted and failed to collect the needed data. What should the engineers do next?
Chemistry
2 answers:
Serjik [45]4 years ago
5 0
From the scenario given in the question, it can be seen that the first probe that the engineers designed melted because its ability to resist high temperature is quite low. So, the next thing the engineers should do is to re-design the probe and this time around they should use materials that will be able to resist the great heat of the sun. 
vesna_86 [32]4 years ago
4 0

Explanation:

Probe melted because the material used in the making of the probe was not that much resistant to the high temperature of the sun. So, now they have to design a probe with material which should have very high resistance to a high temperature so that the probe does not get melt again.

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How many moles of oxygen gas are needed to produce 4 moles of carbon dioxide gas?
11111nata11111 [884]
Answer: 8 moles
Explanation:
Nc2H6= 4 mol
2C2H6 + 7O2 → 4CO2+6H2O
CO2=4/2⋅4
NCO2= 8 moles
( I write this on paper so the letters and format might be confusing) sorry!!
3 0
3 years ago
Sodium nitrate and lead (ii) acetate express your answer as a chemical equation. identify all of the phases in your answer. ente
ICE Princess25 [194]

Answer: 2NaNO_3(aq)+(CH_3COO)_2Pb(aq)\rightarrow 2CH_3COONa(aq)+Pb(NO_3)_2(aq)

Explanation: A double displacement reaction is one in which exchange of ions take place.

The compounds which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.

Thus the exchange of ions take place and all the compounds are soluble so the chemical formulas are followed by the symbol (aq).

3 0
3 years ago
Read 2 more answers
If i increase the [h+] of a solution by 10x, how much will the ph change? and in what direction will ph change?
igomit [66]
For example...
You have solution with [H+] = 0,01M
>>>> pH = -log[H+] = -log0,01 = 2

And you increase the [H+] by 10x ---> 0,01×10 = 0,1M
>>>> pH = -log0,1 = 1

○ pH decrease by 2x
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4 0
3 years ago
What is the mass of 3.35 mol Hg(IO3)2? 1,700 g 1,840 g 1,960 g 2,110 g
vichka [17]

Answer:- 1840 g.

Solution:- We have been given with 3.35 moles of  and asked to calculate it's mass.

To convert the moles to grams we multiply the moles by the molar mass of the compound. Molar mass of the compound is the sum of atomic masses of all the atoms present in it.

molar mass of  = atomic mass of Hg + 2(atomic mass of I) + 6(atomic mass of O)

= 200.59+2(126.90)+6(16.00)

= 200.59+253.80+96.00

= 550.39 gram per mol

Let's multiply the given moles by the molar mass:

3.35mol(\frac{550.39g}{1mol})

= 1843.8 g

Since, there are three sig figs in the given moles of compound, we need to round the calculated my to three sig figs also. So, on rounding off to three sig figs the mass becomes 1840 g.



5 0
3 years ago
The reaction is proceeding at a rate of 0.0080 Ms-1 in 50.0 mL of solution in a system with unknown concentrations of A and B. W
Leokris [45]

Answer:

0.0010 mol·L⁻¹s⁻¹  

Explanation:

Assume the rate law is  

rate = k[A][B]²

If you are comparing two rates,

\dfrac{\text{rate}_{2}}{\text{rate}_{1}} = \dfrac{k_{2}\text{[A]}_2[\text{B]}_{2}^{2}}{k_{1}\text{[A]}_1[\text{B]}_{1}^{2}}= \left (\dfrac{\text{[A]}_{2}}{\text{[A]}_{1}}\right ) \left (\dfrac{\text{[B]}_{2}}{\text{[B]}_{1}}\right )^{2}

You are cutting each concentration in half, so

\dfrac{\text{[A]}_{2}}{\text{[A]}_{1}} = \dfrac{1}{2}\text{ and }\dfrac{\text{[B]}_{2}}{\text{[B]}_{1}}= \dfrac{1}{2}

Then,

\dfrac{\text{rate}_{2}}{\text{rate}_{1}} = \left (\dfrac{1}{2}\right ) \left (\dfrac{1}{2}\right )^{2} = \dfrac{1}{2}\times\dfrac{1}{4} = \dfrac{1}{8}\\\\\text{rate}_{2} = \dfrac{1}{8}\times \text{rate}_{1}= \dfrac{1}{8}\times \text{0.0080 mol$\cdot$L$^{-1}$s$^{-1}$} = \textbf{0.0010 mol$\cdot$L$^{-1}$s$^{-1}$}\\\\\text{The new rate is $\large \boxed{\textbf{0.0010 mol$\cdot$L$^\mathbf{{-1}}$s$^{\mathbf{-1}}$}}$}

8 0
3 years ago
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