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DIA [1.3K]
3 years ago
5

The strength of an acid is affected by the polarity of the bond connected to the acidic hydrogen. The more highly polarized this

bond, the more easily the hydrogen is ionized. Electronegative atoms or groups of atoms present in the structure of an acid can act to withdraw electrons and produce additional polarization. Two common groups of acids to which this principle can be applied are oxoacids and carboxylic acids. In the latter group, the length of the hydrocarbon chain in a carboxylic acid has very little effect on acid strength Longer chains may slightly diminish acidity. Bases act as hydrogen ion acceptors because of the unshared electron pass in their structure. Any group present in a base that withdraws electrons makes these electron pairs less available to accept a hydrogen ion. In contrast, any group that can act as an electron donating group such as hydrocarbon groups (usually represented as II) can increase the base strength. Thus, the addition of electronegative atoms or groups of atoms to the structure of a base decreases the base strength and electron donating groups increase base strength. Many common weak bases are derivatives of ammonia, in which H atom(s) of NH_2 are replaced with other groups.
Arrange the following oxoacids in order of decreasing acid strength. Rank from strongest to weakest acid.
1. HBrO
2. HClO
3. HClO2
4. HClO3
Chemistry
1 answer:
Shtirlitz [24]3 years ago
5 0

Answer:

The answer is "\bold{HClO_3 > HClO_2 >HClO > HBrO}"

Explanation:

We arrange oxoacids to decrease the intensity of acids in this question. Or we may conclude all this from strongest to weakest acids they order oxoacids, that's why above given order is correct.

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You have 627 ml of 5.04 M HCl. Using a volumetric pipet, you take 229 ml of that solution and dilute it to 921 ml in a volumetri
trasher [3.6K]

Answer:

0.653

Explanation:

1)

M1V1 = M2V2

M1 = 5.04 M

V1 = 229 mL ( you take only this volume)

V2 = 921 mL

5.04*229 = M2 * 921

M2 = (5.04*229)/921 Molarity

2)

M1V1 = M2V2

M1 = (5.04*229)/921

V1 = 100 mL

V2= 192 mL

(5.04*229)/921 *100 = M2 * 192

M2 = [(5.04*229)/921 *100]/192 = 0.653 final molarity

8 0
3 years ago
Cho recorded the weather in her town for a week. She wrote down her observations in the table below. Mon Tue Wed Thu Fri Sat Sun
SIZIF [17.4K]

Answer:

If this trend continues, the following week will be cooler, and a large amount of rain will fall.

Explanation:

Patterns and trends can often be found in data sets. During the week that Cho recorded the weather, the temperatures consistently dropped by one to four degrees each day. At the end of the week, the amount of precipitation increased daily.

6 0
4 years ago
A science student observes that a dissolvable antacid tablet acts faster in relieving stomach pain when taken with warm water th
LekaFEV [45]

Answer:the medication would not last as long

Explanation:

Because of the desolving of the tablet so quickly it would

4 0
4 years ago
Read 2 more answers
3. What causes hydrogen bonding?
Fudgin [204]
Hydrogen bonding occurs between a hydrogen atom and an electronegative atom (e.g., oxygen, fluorine, chlorine). The bond is weaker than an ionic bond or a covalent bond, but stronger than van der Waals forces (5 to 30 kJ/mol). A hydrogen bond is classified as a type of weak chemical bond.
5 0
3 years ago
Read 2 more answers
Hydrocarbons, compounds containing only carbon and hydrogen, are important in fuels. The heat of combustion of cyclopentane, C5H
pishuonlain [190]

Answer:

4664.54  kcal of energy is produced on the complete combustion of 416 grams of cyclopentane

Explanation:

Combustion is the process by which hydrocarbons react with oxygen to heat to produce heat energy.

The heat energy produced when one mole of an hydrocarbon is completely burnt or combusted in air is called the heat of combustion

The balanced equation for the complete combustion of cyclopentane (C5H10) is given below:

             2C₅H₁₀ + 15O₂ → 10CO₂ + 10H₂O

                                                             ΔH combustion = 786.6 kcal/mol

What the above equation means is that each time one mole of cyclopentane is completely burnt, 786.6kcal of energy is released.

Hence we need to calculate the number of moles of cyclopentane in 416grams; therefore

No of moles cyclopentane = mass of cyclopentane / molar mass of cycopentane  

                                             = 416 g / 70.1 g/mol

                                             = 5.9343moles

                                             ≅ 5.93 moles of cyclopentane in 416grams

From the question, since the  cyclopentane is completely combusted, it implies that the energy released would be

    1 mole of cyclopentane     = 786.6 kcal of energy

   5.93 moles of cyclopentane would produce    

                                                = 5.93 moles x 786.6kcal/mol

                                                = 4664.54  kcal of energy

6 0
3 years ago
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