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Goshia [24]
3 years ago
12

Do you think crystals formed in conditions that were stable or did they change often?

Chemistry
1 answer:
andreev551 [17]3 years ago
6 0

Answer:

They were made in unstable conditions

Explanation: Im smarty pants

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Im hvaing a hard time getting the right answer
Tanya [424]

Answer:

V=23.9mL

Explanation:

Hello!

In this case for the solution you are given, we first use the mass to compute the moles of CuNO3:

n=2.49g*\frac{1mol}{125.55 g}=0.0198mol

Next, knowing that the molarity has units of moles over liters, we can solve for volume as follows:

M=\frac{n}{V}\\\\V=\frac{n}{M}

By plugging in the moles and molarity, we obtain:

V=\frac{0.0198mol}{0.830mol/L}=0.0239L

Which in mL is:

V=0.0239L*\frac{1000mL}{1L}\\\\V=23.9mL

Best regards!

6 0
3 years ago
Aspirin can be made in the laboratory by reacting acetic anhydride (c4h6o3) with salicylic acid (c7h6o3) to form aspirin (c9h8o4
Temka [501]
V(C₄H₆O₃) = 5.00 mL.
d(C₄H₆O₃) = 1.08 g/mL.
m(C₄H₆O₃) = V(C₄H₆O₃) · d(C₄H₆O₃).
m(C₄H₆O₃) = 5.00 mL · 1.08 g/mL.
m(C₄H₆O₃) = 5.4 g.
n(C₄H₆O₃) = m(C₄H₆O₃) ÷ M(C₄H₆O₃).
n(C₄H₆O₃) = 5.4 g ÷ 102 g/mol.
n(C₄H₆O₃) = 0.0529 mol.
n(C₇H₆O₃) = 2.08 g ÷ 138.1 g/mol.
n(C₇H₆O₃) = 0.015 mol; limiting reactant.
From chemical reaction: n(C₄H₆O₃) : n(C₉H₈O₄) = 1 : 1.
n(C₉H₈O₄) = 0.015 mol.
m(C₉H₈O₄) = 0.015 mol · 180.16 g/mol.
m(C₉H₈O₄) = 2.71 g; theoretical yield.
percent yield od aspirine = 2.57 g ÷ 2.71 g · 100% = 94.83%.

7 0
3 years ago
BRAINLIESTTT ASAP!!! PLEASE HELP ME :)
Ahat [919]

Every science experiment should follow the basic principles of proper investigation so that the results presented at the end are seen as credible.

Observation and Hypothesis. ...

Prediction and Modeling. ...

Testing and Error Estimation. ...

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6 0
3 years ago
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Which of the following is the main reason to use titration in chemistry
zvonat [6]
Most likely to find the equivalence point, equilibrium point, or concentration of a substance or solution!
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4 years ago
Please help me out peps
KengaRu [80]
The answer is the convergent boundary hope this helps
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