15.9 grams is the amount of copper sulfate this reaction will produce.
Given:
- The reaction between copper and sulfur:
- 12.7 grams of copper completely reacts with 3.2 grams of sulfur to give copper sulfide.
To find:
The mass of copper sulfide produced
Solution
Mass of copper used by the scientist = 12.7 g
Mass of sulfur used by the scientist = 3.2 g
Mass of copper sulfide this reaction will produce. =?
According to the law of conservation of mass:
Total mass of reactants = Total mass of products
The total mass of reactants in the reaction = R = 12.7 g + 3.2 g = 15.9 g
The total mass of product formed in the reaction = P
P = R = 15.9 g
Mass of copper sulfide this reaction will produce = 15.9 g
15.9 grams is the amount of copper sulfate this reaction will produce.
Learn more about the law of conservation of mass:
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Answer: Burning wood, souring milk, browning of a cut apple
Answer:
Explanation:
Ba(s) + Mn²⁺ (aq,1M) → Ba²⁺ (aq,1M) + Mn(s)
Ba⁺²(aq) +2e → Ba(s) , E° = −2.90 V
Mn⁺²(aq) +2e → Mn(s), E⁰ =0.80 V
Anode reaction :
Ba(s) → Ba⁺²(aq) +2e E° = −2.90 V
Cathode reaction :
Mn⁺²(aq) +2e → Mn(s) E⁰ =0.80 V
Cell potential = Ecathode - Eanode
Ecell = .80 - ( - 2.90 )
Ecell = 3.7 V .
equilibrium constant ( K ) :
Ecell = .059 log K / n
n = 2
3.7 = .059 log K / 2
log K = 125.42
K = 2.63 x 10¹²⁵ .
Free energy change :
ΔG = - n F Ecell
= - 2 x 96500 x 3.7
= 714100 J
= 7.141 x 10⁵ J .
Mercury(II) oxide, a red solid, decomposes when heated to produce mercury and oxygen gas. Mercury(II) oxide is a red solid. When it is heated, it decomposes into mercury metal and oxygen gas. A reaction is also considered to be a decomposition reaction even when one or more of the products are still compounds.
The molar mass of BF3 is 67.81 g/mol
<em><u> Explanation</u></em>
- Molar mass is the mass of all atoms in a molecule in gram per mole.
- molar mass of a molecule is calculated by adding atomic mass of constituent atom
- use the periodic table to determine the atomic mass of each element in the molecule.
that is;
atomic mass of B = 10.81 g/mol
atomic mass of F = 19 g/mol
- since there 3 atoms of F in BF3 the atomic massof F in BF3= 3 x19 = 57 g/mol
- total molar mass of BF3 = 10.81 g/mol + 57 g/mol = 67.81 g/mol
