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Tresset [83]
3 years ago
14

A copper block rests 38.9 cm from the center of a steel turntable. The coefficient of static friction between the block and the

surface is 0.40. The turntable starts from rest and rotates with a constant angular acceleration of 0.60 rad/s2 . After what time interval will the block start to slip on the turntable
Physics
2 answers:
likoan [24]3 years ago
5 0

Answer:

t = 5.291 s

Explanation:

The copper block starts moving when the force responsible for the circular motion matches the frictional force.

The frictional force is given by μN = μ mg where N = Normal reaction on the block.

μ = coefficient of static friction = 0.4

The force causing circular motion is given by mv²/r = mrw²

mrw² = 0.4 mg

rw² = 0 4g

r = 38.9 cm = 0.389 m

g = 9.8 m/s²

w = √(0.4×9.8/0.389)

w = 3.174 rad/s

We then use equation of motion for the turntable to find out when its angular velocity reaches 3.174 rad/s which is enough to move the block

w = w₀ + αt

w = 3.174 rad/s

w₀ = 0 rad/s ( the turntable was initially at rest)

α = 0.60 rad/s²

t = ?

3.174 = 0 + 0.6t

t = 5.291 s

notka56 [123]3 years ago
5 0

Explanation:

Fmax = μFn

Where,

Fn = normal force

= mg

μ = coefficient of static friction

Fmax = 0.4mg

Angular force, Fi = mω^2r

mω^2 * r = 0.4mg

ω^2 * r = 0.4g

ω = sqrt(0.4 * 9.81/0.389)

= 3.18 rad/s

Using equations of angular motion,

ωf = ωi + αt

ωi = 0 rads

t = ωf/α

= 3.18/0.6

= 5.29 s.

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Answer:

m=417.24 kg

Explanation:  

Given Data

Initial mass of rocket  M = 3600 Kg

Initial velocity of rocket vi = 2900 m/s  

velocity of gas vg = 4300  m/s

Θ = 11° angle in degrees

To find

m = mass of gas  

Solution

Let m = mass of gas    

first to find Initial speed with angle given

So

Vi=vi×tanΘ...............tan angle

Vi= 2900m/s × tan (11°)

Vi=563.7 m/s

Now to find mass

m = (M ×vi ×tanΘ)/( vg + vi tanΘ)

put the values as we have already solve vi ×tanΘ

m = (3600 kg ×563.7m/s)/(4300 m/s + 563.7 m/s)

m=417.24 kg

7 0
3 years ago
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3 0
2 years ago
Convert the arc length of 3.05 degrees into meters.
statuscvo [17]

That depends on the circle's radius, which you neglected to mention.

If the radius is 1 meter, then an arc of 3.05 degrees is 5.32 centimeters long.

If the radius is 1 kilometer, then an arc of 3.05 degrees is 53.2 meters long.

7 0
2 years ago
Please help !! ASAP
umka2103 [35]

Answer:

22) 5.6 Kg.m/s

23) 0.067 Kg

24) 1.16 m/s

Explanation:

Momentum is found by multiplying mass and velocity

P=mv where P is momentum, m is mass of object and v is the velocity

22

Given

Mass, m=2 Kg

Rate, v=2.8 m/s

Relationship

P=mv

Solution

P=mv=2*2.8=5.6 Kg.m/s

23

Given

Momentum, p=0.1 Kg.m/s

Rate, v=1.5 m/s

Relationship

P=mv and making m the subject then

m=\frac {P}{v}

Solution

m=\frac {0.1 Kgm.s}{1.5 m/s}\approx 0.067 Kg

24

Given

Momentum, p=4.9\times 10^{8} Kg.m/s

Mass, m=4.23\times10^{8} Kg

Relationship

P=mv and making v the subject then

v=\frac {P}{m}

Solution

m=\frac {4.9\times 10^{8}  Kgm.s}{4.23\times10^{8} }\approx 1.16 m/s

5 0
2 years ago
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