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3 years ago

I need help real quick. Please help me!!

Physics

1 answer:

dimaraw [331]3 years ago

4 0

<h3><u>Answer;</u></h3>

D) Standing wave

<h3><u>Explanation;</u></h3>

Standing wave also called stationary wave is a wave which oscillates in time but whose peak amplitude profile does not move in space.
A standing wave pattern is a vibrational pattern created within a medium when the vibrational frequency of the source causes reflected waves from one end of the medium to interfere with incident waves from the source.
Examples of standing waves include the vibration of a violin string and electron orbitals in an atom.

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If the distance d (in meters) traveled by an object in time t (in seconds) is given by the formula d=a+bt2, the si units of a an

ss7ja [257]

Distance , d = a+b $t^2$

The unit of d is in meter and t is in seconds.

So the unit of a a must be meter.

Now we have unit of b $t^2$ is meter.

So unit of b* $second^2$ = meter

Unit of b = meter/ $second^2$

So unit of a = m and unit of b = m/ $s^2$ .

8 0

3 years ago

Standing waves are created in the four strings shown in Figure 25. All strings have the same mass per unit length and are under

nadezda [96]

Answer:

The rank of the frequencies from largest to smallest is

The largest frequency of oscillation is given by the string in option D

The second largest frequency of oscillation is given by the string in option B

The third largest frequency of oscillation is given by the string in option A

The smallest frequency of oscillation is given by the string in option C

Explanation:

The given parameters are;

The mass per unit length of all string, m/L = Constant

The tension of all the string, T = Constant

The frequency of oscillation, f, of a string is given as follows;

$f = \dfrac{(n + 1) \times \sqrt{\dfrac{T}{m/L} } }{2 \cdot L}$

Where;

T = The tension in the string

m = The mass of the string

L = The length of the string

n = The number of overtones

$Therefore, \ {\sqrt{\dfrac{T}{m/L} } } = Constant \ for \ all \ strings = K$

For the string in option A, the length, L = 27 cm, n = 3 we have;

$f_A = \dfrac{(n + 1) \times \sqrt{\dfrac{T}{m/L} } }{2 \cdot L} = \dfrac{(3 + 1) \times K }{2 \times 27} = \dfrac{2 \times K}{27} \approx 0.07407 \cdot K$

For the string in option B, the length, L = 30 cm, n = 4 we have;

$f_B = \dfrac{(n + 1) \times \sqrt{\dfrac{T}{m/L} } }{2 \cdot L} = \dfrac{(4 + 1) \times K }{2 \times 30} = \dfrac{ K}{12} \approx 0.08 \overline 3\cdot K$

For the string in option C, the length, L = 30 cm, n = 3 we have;

$f_C = \dfrac{(n + 1) \times \sqrt{\dfrac{T}{m/L} } }{2 \cdot L} = \dfrac{(3 + 1) \times K }{2 \times 30} = \dfrac{K}{15} \approx 0.0 \overline 6 \cdot K$

For the string in option D, the length, L = 24 cm, n = 4 we have;

$f_D = \dfrac{(n + 1) \times \sqrt{\dfrac{T}{m/L} } }{2 \cdot L} = \dfrac{(4 + 1) \times K }{2 \times 24} = \dfrac{5 \times K}{48} \approx 0.1041 \overline 6 \cdot K$

Therefore, we have the rank of the frequency of oscillations of th strings from largest to smallest given as follows;

1 ) $f_D$ 2) $f_B$ 3) $f_A$ 4) $f_C$

8 0

3 years ago

Many arlines restrict maximum mass of a case to 23 kg why

Alexxandr [17]

Answer:

weight

Explanation:

the weight of an object on an airline is one of the most important thing a pilot has to consider when prepping a flight and that is because if there is too much weight then the plane simply can't fly. imagine if everyone wanted to bring a 50 kg box. there are at least 200 people. that alone is 10,000 lg of weight than you have to factor in all the people, wires on the plane, and certain appliances that some planes have.

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3 years ago

A movie stunt performer is filming a scene where he swings across a river on a vine. The safety crew must use a vine with enough

Julli [10]

Answer:

1125.66956 N

Explanation:

m = Mass of stunt performer

g = Acceleration due to gravity = 9.81 m/s²

v = Velocity of the swing = 7 m/s

T = Tension

r = Radius of the swing = Length of vine = 11.5 m

From the free body diagram

$T-mg-m\frac{v^2}{r}=0\\\Rightarrow T=mg+m\frac{v^2}{r}\\\Rightarrow T=m(g+\frac{v^2}{r})\\\Rightarrow T=80(9.81+\frac{7^2}{11.5})\\\Rightarrow T=1125.66956\ N$

The minimum tension force the vine must be able to support without breaking is 1125.66956 N

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3 years ago

What is the speed of a bird of mass 8kg which has kinetic energy of 8836J?

Natali [406]

Answer:

i dont know

Explanation:

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3 years ago