Answer:
1.3 × 10⁸ e⁻
Explanation:
When a honeybee flies through the air, it develops a charge of +20 pC = + 20 × 10⁻¹² C. This is a consequence of losing electrons (negative charges). The charge of 1 mole of electrons is 96468 C (Faraday's constant). The moles of electrons representing 20 pC are:
20 × 10⁻¹² C × (1 mol e⁻/ 96468 C) = 2.1 × 10⁻¹⁶ mol e⁻
1 mole of electrons has 6.02 × 10²³ electrons (Avogadro's number). The electrons is 2.1 × 10⁻¹⁶ moles of electrons are:
2.1 × 10⁻¹⁶ mol e⁻ × (6.02 × 10²³ e⁻/ 1 mol e⁻) = 1.3 × 10⁸ e⁻
"Constant velocity" is practically a definition for zero acceleration.
This would be typical of an elastic collision.
Answer:
72.1 m
Explanation:
Hello!
When the walker walks west, each block he walks will be of 100 m, so the walker walked 4*100m = 400 m west.
Similarly, when the walker walks south, he walks 20 meters per block, therefore, the walker walked 4*20 m = 80 m south.
Since the directions west and south are perpendicular, the distance between the start ad end point is:
d = √(400^2 + 80^2) m = 407.92 m
However the walker traveled 480 m
Therefore, the walker traveled 480 - 407.9 m = 72.1 m farther than the actual distance
