We know density = Mass / Volume
So Volume = Mass/Density
Volume = Area * Thickness
![Area = 50 ft^2 = 4.645152 m^2\\ \\Mass = 7 oz = 0.198447 kg\\ \\Density = 2.70 g/cm^3 = 2700 kg/m^3\\ \\Substituting \\ \\4.645152 *t = \frac{0.198447}{2700} \\ \\t = 1.58*10^{-5}m = 1.58*10^{-2}mm](https://tex.z-dn.net/?f=Area%20%3D%2050%20ft%5E2%20%3D%204.645152%20m%5E2%5C%5C%20%5C%5CMass%20%3D%207%20oz%20%3D%200.198447%20kg%5C%5C%20%5C%5CDensity%20%3D%202.70%20g%2Fcm%5E3%20%3D%202700%20kg%2Fm%5E3%5C%5C%20%5C%5CSubstituting%20%5C%5C%20%5C%5C4.645152%20%2At%20%3D%20%5Cfrac%7B0.198447%7D%7B2700%7D%20%5C%5C%20%5C%5Ct%20%3D%201.58%2A10%5E%7B-5%7Dm%20%3D%201.58%2A10%5E%7B-2%7Dmm)
So the approximate thickness of the foil in millimeters = ![1.58*10^{-2}mm](https://tex.z-dn.net/?f=1.58%2A10%5E%7B-2%7Dmm)
I would think something like fire or a torch because that seems like it means heat or maybe a campfire picture
<em>mass (m)= 5 kg</em>
<em>height (h)= 9m </em>
<em>gravity (g)= 9.8 m/s^2</em>
It has Potential energy. (PE)
• PE = mgh
Replacing:
PE = 5 * 9.8 * 9 = 441 Joules
Answer:
the final angular speed of the wheel at the bottom is 25.5 rad/s
Explanation:
The computation of the final angular speed of the wheel at the bottom is as follows:
As we know that
![W_f = W_{in} + \alpha t\\\\= 2.5 + (2 \times 11.5)\\\\= 2.5 + 23\\\\= 25.5 rad/s](https://tex.z-dn.net/?f=W_f%20%3D%20W_%7Bin%7D%20%2B%20%5Calpha%20t%5C%5C%5C%5C%3D%202.5%20%2B%20%282%20%5Ctimes%2011.5%29%5C%5C%5C%5C%3D%202.5%20%2B%2023%5C%5C%5C%5C%3D%2025.5%20rad%2Fs)
Hence, the final angular speed of the wheel at the bottom is 25.5 rad/s
We simply applied the above formula so that the final angular speed could come