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yarga [219]
3 years ago
9

A student lifts a school bag from the ground and puts it on his shoulders 1.5m above the ground. A force of 5N is acting on an o

bject. Calculate the work done by him on the school bag.
Physics
1 answer:
Paul [167]3 years ago
4 0

Answer:

w = 7.5 [J]

Explanation:

We must remember the definition of mechanical work, which tells us that work is equal to the product of force by distance. This force must be applied in the direction of movement. So we have the following equation:

w = F*d

where:

w = work [J]

F = force [N]

d = distance [m]

Now replacing we have:

w = 5*1.5

w = 7.5 [J]

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Answer: 100 suns

Explanation:

We can solve this with the following relation:

\frac{d}{x_{sunball-pinhole}}=\frac{D}{x_{sun-pinhole}}

Where:

d=17.91 mm =17.91(10)^{-3}  m is the diameter of a dime

D is the diameter of the Sun

x_{sun-pinhole}=150,000,000 km=1.5(10)^{11}  m is the distance between the Sun and the pinhole

x_{sunball-pinhole}=100 d=1.791 m is the amount of dimes that fit in a distance between the sunball and the pinhole

Finding D:

D=\frac{d}{x_{sunball-pinhole}}x_{sun-pinhole}

D=\frac{17.91(10)^{-3}  m}{1.791 m} 1.5(10)^{11}  m

D=1.5(10)^{9}  m This is roughly the diameter of the Sun

Now, the distance between the Earth and the Sun is one astronomical unit (1 AU), which is equal to:

1 AU=149,597,870,700 m

So, we have to divide this distance between D in order to find how many suns could it fit in this distance:

\frac{149,597,870,700 m}{1.5(10)^{9}  m}=99.73 suns \approx 100 suns

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What value is closest to the mass of the atom?....
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A parachutist of mass 56.0 kg jumps out of a balloon at a height of 1400 m and lands on the ground with a speed of 5.10 m/s. How
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Answer:

769,048.28Joules

Explanation:

A parachutist of mass 56.0 kg jumps out of a balloon at a height of 1400 m and lands on the ground with a speed of 5.10 m/s. How much energy was lost to air friction during this bump

The energy lost due to friction is expressed using the formula;

Energy lost  = Potential Energy + Kinetic Energy

Energy lost  = mgh + 1/2mv²

m is the mass

g is the acceleration due to gravity

h is the height

v is the speed

Substitute the given values into the formula;

Energy lost  = 56(9.8)(1400) + 1/2(56)(5.10)²

Energy lost  = 768,320 + 728.28

Energy lost  = 769,048.28Joules

<em>Hence the amount of energy that was lost to air friction during this jump is 769,048.28Joules</em>

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