1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
yarga [219]
3 years ago
9

A student lifts a school bag from the ground and puts it on his shoulders 1.5m above the ground. A force of 5N is acting on an o

bject. Calculate the work done by him on the school bag.
Physics
1 answer:
Paul [167]3 years ago
4 0

Answer:

w = 7.5 [J]

Explanation:

We must remember the definition of mechanical work, which tells us that work is equal to the product of force by distance. This force must be applied in the direction of movement. So we have the following equation:

w = F*d

where:

w = work [J]

F = force [N]

d = distance [m]

Now replacing we have:

w = 5*1.5

w = 7.5 [J]

You might be interested in
What is the current in a 10V Circuit if the resistance is 2 ohms
VladimirAG [237]
V=IR can be changed to V/R=I so 10V/2 ohms = 5amps so 5 amps is your answer boss
8 0
3 years ago
A single loop of wire with an area of 0.0780 m2 is in a uniform magnetic field that has an initial value of 3.80 T, is perpendic
Katarina [22]

Answer:

The induced current is 26.7 mA

Explanation:

Given;

area of the loop, A = 0.078 m²

initial magnetic field, B₁ = 3.8 T

change in the magnetic field strength, dB/dt = 0.24 T/s

The induced emf is calculated as;

emf = - \frac{d \phi}{dt} \\\\emf = -\frac{dB.A}{dt} \\\\emf = A (\frac{dB}{dt} )\\\\emf = 0.078(0.24)\\\\emf = 0.0187 \ V

The resistance of the loop = 0.7 Ω

The induced current is calculated as;

V = IR\\\\I = \frac{V}{R} = \frac{emf}{R} = \frac{0.0187}{0.7} = 0.0267 \ A = 26.7 \ mA

4 0
3 years ago
A student in Denver (altitude = 1 mile = 1609 m above sea level) brings a physics book of mass 1.3 kg to the top of a ten story
Nesterboy [21]

Answer:

Explanation:

Potential energy is the energy of a body due to is virtue of rest.

Potential energy is given as mgh

g is a constant and it is 9.81m/s²

And also the mass of the body is given as 1.3kg

Now the height of the body is

He took a book to a storey building of height 26m

He still holds the book 151 cm (1.51m) above the house.

The house is on an altitude of 1609m from the sea level.

Total Ug with out the sea level is

Ug=mgh

Ug=1.3 × 9.81 ×(26+1.51)

Ug=350.84J

Then, the potential energy due to the sea level is given as

Ug=mgh

Where g = 1/6371 m/s²

Therefore

Ug=mgh

Ug=1.3 × 1/6371 ×1609

Ug=0.328J

Total energy = 0.328+350.84

Ug=351.17J

8 0
3 years ago
Like magnetism, static electricity can attract and repel.<br> True<br> False
earnstyle [38]
The answer to the question is True
5 0
3 years ago
Read 2 more answers
Which of the following situations would produce an average velocity of zero?
MariettaO [177]
The correct answer is A
4 0
3 years ago
Other questions:
  • a boat accelerates at a rate of 6.0m/s down a river. how much time will it take the boat to speed up to 7.0m/s?
    7·1 answer
  • Marta, Cato, and Juan plan a skit to illustrate one of the methods of charging.
    8·2 answers
  • Which of the following statements is true?
    9·2 answers
  • A student of weight 659 N rides a steadily rotating Ferris wheel (the student sits upright). At the highest point, the magnitude
    7·1 answer
  • Completenlo por favor
    12·1 answer
  • According to Ohm’s law, which combination of units is the same as the unit for resistance? volt ÷ ampere ampere × volt volt + am
    6·2 answers
  • 1. Using the data table below, model (draw) the orbital motion of the two planets (D and
    7·1 answer
  • What is the final temperature if it requires 5000 J of heat to warm 2.38892 x10-2 kg of water that starts at 5oC? Remember Cp fo
    7·1 answer
  • PLEASE HELP! I'LL GIVE BRAINLEST​
    10·1 answer
  • How much work does it take to accelerate from 5 m/s to 10 m/s?
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!