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AURORKA [14]
3 years ago
10

I need help with #4 and #5?

Physics
1 answer:
algol [13]3 years ago
3 0

A

Explanation:

just  pick a

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A person walks 24 meters at 3 m/s. How long did it take them
asambeis [7]

Hi my dear friend,

2m*30 = 60m

~Thank you

4 0
4 years ago
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the air in a tire is initially at 380 kpa, 20 C, when the tire volume is 0.120 m^3. as the tire is warmed by the sun, the pressu
castortr0y [4]

Answer:

final temperature is 364.32 K

mass of air is 0.5423 kg

Explanation:

given data

pressure p1 = 380 kPa

volume v1 =  0.120 m³

temperature = 20°C = 20 + 273 = 293 K

pressure p2 = 3450 kPa

volume v2 =  5% increase

to find out

final temperature and the mass

solution

we consider here ideal gas

so equation is

p1v1 / t1 = p2v2/t2

put here all value and find t2

and v2 is = 0.120 ( 1 + 0.05) = 0.126 m³

so

t2 = p2v2/ p1v1 × t1

t2 = (450 × 0.126) /  (380 × 0.120)  ×  293

t2 = 364.32 K

so final temperature is 364.32 K

and

mass = p2v2 / Rt2

here R gas constant is 0.287 kJ/kg.K

so

mass = (450 × 0.126) / (0.287 × 364.32 )

mass = 0.5423

so mass of air is 0.5423 kg

7 0
3 years ago
Which best describes what is required for any sound wave to travel?
olganol [36]

Answer:

Any medium solid, liquid or gas is required for sound waves to travel.

Explanation:

A sound wave requires a medium to travel. Sound waves are mechanical waves that is why these waves require a medium to travel. Sound waves can travel through solids, liquids, and gases.

In solids, the particles of the medium are closely packed together as compared to liquids and gases. In liquids, particles are less tightly packed and almost negligible in gases.

Therefore sound waves produce vibration in the dense or solid medium. Denser the medium faster the sound waves travel. However sound waves can not travel through empty space.

8 0
4 years ago
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A solid steel cylinder is standing (on one of its ends) vertically on the floor. The length of the cylinder is 3.2 m and its rad
maksim [4K]

To solve this problem it is necessary to apply the concepts related to Young's Module and its respective mathematical and modular definitions. In other words, Young's Module can be expressed as

\Upsilon = \frac{F/A}{\Delta L/L_0}

Where,

F = Force/Weight

A = Area

\Delta L= Compression

L_0= Original Length

According to the values given we have to

\Upsilon_{steel} = 200*10^9Pa

\Delta L = 5.6*10^{-7}m

L_0 = 3.2m

r= 0.59m \rightarrow A = \pi r^2 = \pi *0.59^2 = 1.0935m^2

Replacing this values at our previous equation we have,

\Upsilon = \frac{F/A}{\Delta L/L_0}

200*10^9 = \frac{F/1.0935}{5.6*10^{-7}/3.2}

F = 38272.5N

Therefore the Weight of the object is 3.82kN

4 0
3 years ago
Can anyone heelp me plzz
lina2011 [118]

Answer:

the ans is D... good luck

3 0
3 years ago
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