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Mila [183]
4 years ago
11

An observer sees a full moon in the night sky. What will the Moon's phase be 10 days later?

Physics
1 answer:
algol [13]4 years ago
5 0
I'm pretty sure the moon would be a crescent within the 10 day period because it takes about 28 days for the moon to go through the different stages.
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Is god real??? i wanna know
NemiM [27]
In my opinion, yes the bible tell us that "For God so loved<span> the world that he gave</span><span> his one and only Son,</span><span> that whoever believes</span><span> in him shall not perish but have eternal life" 
So my answer is yes</span>
6 0
3 years ago
Read 2 more answers
Find an equation in x and y for the line tangent to the curve ()=4,()=cos() at the point where =4.
m_a_m_a [10]

An equation in x and y for the line tangent to the curve ()=4,()=cos() at the point where =4 is x(t)=2t+2,y(t)=t^4.

<h3>What is tangent?</h3>

In calculation, the digression line to a plane bend at a given point is the straight line that "simply contacts" the bend by then. Leibniz characterized it as the line through a couple of boundlessly close focuses on the bend. The chart of digression is intermittent, implying that it rehashes the same thing endlessly. In contrast to sine and cosine in any case, digression has asymptotes isolating every one of its periods. The space of the digression capability is all genuine numbers with the exception of at whatever point cos⁡(θ)=0, where the digression capability is vague. Assuming they stroll in an orderly fashion, they are fundamentally following a digression way for the shape that is made inside the fencing.

Learn more about tangent, refer:

brainly.com/question/12585907

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7 0
2 years ago
3. One atom of silicon can properly be combined in a compound with A. One atom of chlorine. B. Three atoms of hydrogen. C. Two a
Paraphin [41]

C :<em>2 atoms of Oxygen can probably join 1 Silicon Atom</em>

4 0
3 years ago
An l-c cirucit with a 70 mh inductor and a ,54 F capacitor oscillates. The maximum charge on the capacitor is 11.5 C. What are t
Oxana [17]

This question is incomplete, the complete question is;

An l-c cirucit with a 70 mh inductor and a 0.54 μF capacitor oscillates. The maximum charge on the capacitor is 11.5 μC. What are the oscillation frequency and the maximum current in this circuit ;

Options

a) 1.07 kHz, 63.4 mA

b) 4.38 kHz, 101.3 mA

c) 6.74 kHz, 55.7 mA

d) 2.31 kHz, 93.5 mA

e) 0.82 kHz, 59.1 mA

Answer:

the oscillation frequency and the maximum current in this circuit are; 0.82 kHz and 59.1 mA respectively.

so Option e) 0.82 kHz, 59.1 mA is the correct answer

Explanation:

Given that;

inductor L = 70 mH = 70 × 10⁻³ H

Capacitor C = 0.54 μf = 0.54 × 10⁻⁶ f

Qmax on capacitor = 11.5 μf = 11.5 × 10⁻⁶ c

oscillation frequency in L-C circuit;

f = 1/2π√(LC)

we substitute our values;

f = 1/2π√(70 × 10⁻³ × 0.54 × 10⁻⁶  )

f = 0.0818 × 10⁴ Hz

f = 0.082 × 10³ Hz ≈ 0.82 kHz

Maximum circuit in L-C circuit is given by

I_max = Qmax/√(LC)

we substitute

I_max = 11.5 × 10⁻⁶ / √(70 × 10⁻³ × 0.54 × 10⁻⁶  )

= 59.1 × 10³ A ≈  59.1 mA

Therefore the oscillation frequency and the maximum current in this circuit are; 0.82 kHz and 59.1 mA respectively.

so Option e) 0.82 kHz, 59.1 mA is the correct answer

5 0
3 years ago
A 1500-kg sedan goes through a wide intersection traveling from north to south when it is hit by a 2200-kg SUV traveling from ea
astra-53 [7]

Answer:

Velocity of Sedan = 21 m/s

Velocity of SUV = 12 m/s

Explanation:

As we know that deceleration due to friction force is given as

a = - \mu g

so we have

a = -(0.75)(9.81)

a = -7.36 m/s^2

now the two cars comes to rest at a point which is at position of 5.39 m West and 6.43 m South

so net displacement of the car is given as

d = \sqrt{5.39^2 + 6.43^2}

d = 8.39 m

now the velocity of the two cars just after the impact is given as

v^2 - v_i^2 = 2a d

0 - v_i^2 = 2(-7.36)(8.39)

v_i = 11.11 m/s

direction of the motion is given as

tan\theta = \frac{6.43}{5.39}

\theta = 50 degree South of West

now we can use momentum conservation as there is no external force on it

Momentum conservation in North to south direction

m_1 v_1 = (m_1 + m_2) vsin\theta

1500 v_1 = (1500 + 2200) (11.11) sin50

v_1 = 21 m/s

Similarly momentum conservation towards West direction

m_2 v_2 = (m_1 + m_2) vsin\theta

2200 v_2 = (1500 + 2200) (11.11) cos50

v_2 = 12 m/s

5 0
3 years ago
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