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Lesechka [4]
3 years ago
10

how much energy is stored in a 7.0 cm spring that has a spring constant of 500 N/m when it is stretched 3.0 cm​

Physics
1 answer:
zaharov [31]3 years ago
8 0
<h3>Answer:</h3>

12250 J

<h3>Explanation:</h3>

<em>elastic potential energy = 0.5 × spring constant × (extension)2</em>

spring constant = 500

extension =  7cm

7^2=49

0.5 × 500 × 49 = 12250 J or 12.25kJ

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<u>Explanation</u>

When we jump on a trampoline, our body has kinetic energy that changes over time. Our kinetic energy is greatest, just before we hit the trampoline on the way down and when you leave the trampoline surface on the way up. Our kinetic energy is 0 when you reach the height of your jump and begin to descend and when are on the trampoline, about to propel upwards.

Potential energy changes along with kinetic energy. At any time, your total energy is equal to your potential energy plus your kinetic energy. As we go up, the kinetic energy converts into potential energy.

Hooke's law is another form of potential energy. Just as the trampoline is about to propel us up, your kinetic energy is 0 but your potential energy is maximized, even though we are at a minimum height. This is because our potential energy is related to the spring constant and Hooke's Law.

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When most chemical reactions take place, some ____ in the reactants must be broken, a process that requires energy.
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Juli2301 [7.4K]

Answer:

<h2>23.33 kg </h2>

Explanation:

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To learn more about the plasma state refer;

brainly.com/question/5496865

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