Answer:
300Nm
Explanation:
work = force x distance = 60x5=300
<span> Let,
initial velocity = v m/sec,
Angle, x = 40 degrees,
horizontal-componant = v.cos(x) = 12 m/sec,
OR,
v = 12 / cos(40) = 12/0.766 = 15.67 meters/sec >================< ANSWER </span> Source(s): Fazaldin A <span> · 4 years ago </span>
Answer:
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Explanation:
The frictional force is 218.6 N
Explanation:
The block in the problem is at rest along the inclined surface: this means that the net force acting along the direction parallel to the incline must be zero.
There are two forces acting along this direction:
- The component of the weight parallel to the incline, downward along the plane, of magnitude

where
m = 46 kg is the mass
is the acceleration of gravity
is the angle of the incline
- The (static) frictional force, acting upward, of magnitude 
Since the block is in equilibrium, we can write

And substituting, we find the force of friction:

Learn more about frictional force along an inclined plane:
brainly.com/question/5884009
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