The prop blades of an airplane spin with a linear velocity of 875 m/s and have a centripetal acceleration on the farthest edge o
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<h2>Answer:442758.96N</h2>
Explanation:
This problem is solved using Bernoulli's equation.
Let be the pressure at a point.
Let be the density fluid at a point.
Let be the velocity of fluid at a point.
Bernoulli's equation states that for all points.
Lets apply the equation of a point just above the wing and to point just below the wing.
Let be the pressure of a point just above the wing.
Let be the pressure of a point just below the wing.
Since the aeroplane wing is flat,the heights of both the points are same.
So,
Force is given by the product of pressure difference and area.
Given that area is .
So,lifting force is
Answer:
The frequency of sound heard by the boy is 1181 Hz.
Explanation:
Given that,
Frequency of sound from alarm
Speed = -8.25 m/s
Negative sign show the boy riding away from the car
Speed of sound = 343
We need to calculate the heard frequency
Using formula of frequency
Where, = frequency of source
= speed of observer
= speed of source
= speed of sound
Put the value into the formula
here, source is at rest
Hence, The frequency of sound heard by the boy is 1181 Hz.