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777dan777 [17]
2 years ago
12

A cow standing atop a building in Times Square recalled a funny joke and began to laugh. The uncontrollable laughter caused the

cow to fall over the side of the building. He fell for a time period of 3.5 s and landed in a bed of bushes. How fast was the cow moo-ving when he reached the bushes?
Which equation should be used to solve the problem?
Physics
1 answer:
aliina [53]2 years ago
4 0

Answer:

Vf = 34.3 m/s

1st equation of motion was used to solve.

Explanation:

In order to find the final speed of the cow, when it hits the bushes, we can use first equation of motion:

Vf = Vi + gt

where,

Vf = Final Velocity of Cow = ?

Vi = Initial Velocity of Cow = 0 m/s

g = acceleration due to gravity = 9.8 m/s²

t = time taken = 3.5 s

Therefore,

Vf = 0 m/s + (9.8 m/s²)(3.5 s)

<u>Vf = 34.3 m/s</u>

<u>1st equation of motion was used to solve.</u>

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The (more) speed an object has, the (lower) the potential energy and the (higher) the kinetic energy. (I believe that is correct but it’s been a while since I’ve done this)
8 0
2 years ago
What are the limitations of using solar panels?​
umka21 [38]
Location & Sunlight Availability.
Solar Panels use a large amount of space.
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8 0
2 years ago
A 2.00 kg block hangs from a spring balance calibrated in Newtons that is attached to the ceiling of an elevator.(a) What does t
tresset_1 [31]

Answer:

Part a)

Reading = 2.00 kg

Part b)

Reading = 2.00 kg

Part c)

Reading = 4.04 kg

Part d)

from t = 0 to t = 4.9 s

so the reading of the scale will be same as that of weight of the block

Then its speed will reduce to zero in next 3.2 s

from t = 4.9 to t = 8.1 s

The reading of the scale will be less than the actual mass

Explanation:

Part a)

When elevator is ascending with constant speed then we will have

F_{net} = 0

T - mg = 0

T = mg

So it will read same as that of the mass

Reading = 2.00 kg

Part b)

When elevator is decending with constant speed then we will have

F_{net} = 0

T - mg = 0

T = mg

So it will read same as that of the mass

Reading = 2.00 kg

Part c)

When elevator is ascending with constant speed 39 m/s and acceleration 10 m/s/s then we will have

F_{net} = ma

T - mg = ma

T = mg + ma

Reading is given as

Reading = \frac{mg + ma}{g}

Reading = 2.00\frac{9.81 + 10}{9.81}

Reading = 4.04 kg

Part d)

Here the speed of the elevator is constant initially

from t = 0 to t = 4.9 s

so the reading of the scale will be same as that of weight of the block

Then its speed will reduce to zero in next 3.2 s

from t = 4.9 to t = 8.1 s

The reading of the scale will be less than the actual mass

3 0
3 years ago
Calculate the molarity of a 10. 0% cacl₂ solution. The density of the solution is 1. 0835 g/cm³.
brilliants [131]

The molarity of 10% CaCl2 is 0.9%

concentration of the given salt CaCl₂ = 10%

Density of a solution = 1.0835 g/cm³

Volume = m / d

= 100 / 1.0835

= 92.29 litres

Density = mass / volume

1.0835 × 92.29 = mass

mass = 99.99 gram

Thus the molarity can be calculated by = moles of solute / volume of solution multiplied by 100

= 0.9008/ 92.29 X 100 %

= 0.009 X 100 %

= 0.9 %

The molarity of 10% CaCl2 is 0.9%

To know more about density and molarity you may visit the link which is mentioned below:

brainly.com/question/10710093

#SPJ4

5 0
1 year ago
Which law of physics relates electric fields and current
riadik2000 [5.3K]

Answer:

Ohms law

Explanation:

Which states that the current flowing through any cross-section of the conductor is directly proportional to the potential differenceapplied across its end, provided physical conditions like temperature and pressure remain constant.

7 0
3 years ago
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