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777dan777 [17]
2 years ago
12

A cow standing atop a building in Times Square recalled a funny joke and began to laugh. The uncontrollable laughter caused the

cow to fall over the side of the building. He fell for a time period of 3.5 s and landed in a bed of bushes. How fast was the cow moo-ving when he reached the bushes?
Which equation should be used to solve the problem?
Physics
1 answer:
aliina [53]2 years ago
4 0

Answer:

Vf = 34.3 m/s

1st equation of motion was used to solve.

Explanation:

In order to find the final speed of the cow, when it hits the bushes, we can use first equation of motion:

Vf = Vi + gt

where,

Vf = Final Velocity of Cow = ?

Vi = Initial Velocity of Cow = 0 m/s

g = acceleration due to gravity = 9.8 m/s²

t = time taken = 3.5 s

Therefore,

Vf = 0 m/s + (9.8 m/s²)(3.5 s)

<u>Vf = 34.3 m/s</u>

<u>1st equation of motion was used to solve.</u>

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The angular quantities: angular displacement, angular velocity, angular acceleration, are defined in a very similar way to the l
Lena [83]

Answer: [tex]12.415 rad.s^{-1}[/tex]

Explanation: Angular velocity is the rate of change in angular displacement.

We know that:

Angular velocity,      \omega= \frac{\Delta \theta}{t}....................(1)

where:

  • t= time
  • \Delta \theta = angular displacement in radians

<u>Given that:</u>

  • t = 4.10 s
  • Δθ = 50.9 radian

Putting the respective values in eq. (1)

\omega = \frac{50.9}{4.10}

\omega = 12.415 rad.s^{-1}

4 0
3 years ago
It is known that the gravitational force of attraction between two alpha particles is much weaker than the electrical repulsion.
natali 33 [55]

Answer:

<em>The ratio of gravitational force to electrical force is 3.19 x 10^-36 </em>

<em></em>

Explanation:

mass of an alpha particle = 6.64 x 10^{-27} kg

charge on an alpha particle = +2e = +2(1.6 x 10^{-19} C) = 3.2 x 10^{-19} C

distance between particles = d

For gravitational attraction:

The force of gravitational attraction F = \frac{Gm^{2} }{r^{2} }

where G = gravitational constant = 6.67 x 10^{-11} m^3 kg^-1 s^-2

r = the distance between the particles = d

m = the mass of each particle

therefore, gravitational force = \frac{6.67*10^{-11}*(6.64*10^{-27} )^{2}  }{d^{2} } = \frac{2.94*10^{-63} }{d^{2} }  Newton

For electrical repulsion:

Electrical force between the particles = \frac{-kQ^{2} }{r^{2} }

where k is the Coulomb's constant = 9.0 x 10^{9} N•m^2/C^2

r = distance between the particles = d

Q = charge on each particle

therefore, electrical force = \frac{-9*10^{9}*(3.2*10^{-19} )^{2}  }{d^{2} } = \frac{-9.216*10^{-28} }{d^{2} } Newton

the negative sign implies that there is a repulsion on the particles due to their like charges.

Ratio of the magnitude of gravitation to electrical force = \frac{2.94*10^{-63} }{9.216*10^{-28} }

==> <em>3.19 x 10^-36 </em>

8 0
3 years ago
If you let him have Czechoslovakia, he is going to.​
valentinak56 [21]

I - ok. Czechoslovakia is officially taken.

4 0
2 years ago
A skier rides a ski-lift up to the top of the mountain, 1600 m above sea level. If the skier has a mass of 74 kg, how much poten
statuscvo [17]

Answer:

I think it is 1.16 MJ

Explanation:

PE=mgh

PE=(74)(9.81)(1600)= 1,161,504J = 1.16MJ

3 0
3 years ago
The kinetic energy of an object with a mass of 6.8 kg and a velocity of 5.0 m/s is J. (Report the answer to two significant figu
abruzzese [7]

Answer:

\boxed{\sf Kinetic \ energy \ (KE) = 85 \ J}

Given:

Mass (m) = 6.8 kg

Speed (v) = 5.0 m/s

To Find:

Kinetic energy (KE)

Explanation:

Formula:

\boxed{ \bold{\sf KE =  \frac{1}{2} m {v}^{2} }}

Substituting values of m & v in the equation:

\sf \implies KE =  \frac{1}{2}  \times 6.8 \times  {5}^{2}

\sf \implies KE = \frac{1}{ \cancel{2}}  \times  \cancel{2} \times 3.4 \times 25

\sf \implies KE =3.4 \times 25

\sf \implies KE = 85 \: J

8 0
3 years ago
Read 2 more answers
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