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tresset_1 [31]
3 years ago
13

A loop of wire lays flat on a horizontal surface in an area with uniform magnetic field directed vertically down. Magnetic field

suddenly grows stronger. While magnetic field is changing, the induced current in the loop as viewed from above is:
A. clockwise
B. counterclockwise
C. zero
D. There is not enough information to answer this question
Physics
1 answer:
zimovet [89]3 years ago
4 0

Answer:

B. counterclockwise

Explanation:

We shall apply Lenz's law to find direction of induced current . According to it , direction of induced current is such that the magnetic field produced  by it will try to nullify the change in  magnetic field that produces it. Increase in magnetic field in down ward direction is producing it so to nullify it , magnetic field induced will be in upward direction.  For it current induced will be anticlockwise.

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Suppose that you hear a clap of thunder 16 s after seeing the associated lightning strike. How far are you from the lightning st
riadik2000 [5.3K]

Answer:

d=5.376km

Explanation:

Since <em>light is so fast</em> we can assume no time passes between the lightning strikes and we observe it. We want to know then how far away did the strike occur for the sound to take 16s to reach our ears. Since the definition of velocity tells us that v=d/t, we can write d=vt=(336m/s)(16s)=5376m=5.376km

4 0
3 years ago
A certain corner of a room is selected as the origin of a rectangular coordinate system. If a fly is crawling on an adjacent wal
Helga [31]

Answer:

2.59 m

Explanation:

Coordinates of origin = (0, 0)

Coordinates of Point p where the fly reach = (2.3 m, 1.2 m)

Use the distance formula of coordinates to find the distance between the origin and the point P.

d=\sqrt{\left ( x_{2}-x_{1} \right )^{2}+\left ( y_{2}-y_{1} \right )^{2}}

d=\sqrt{\left ( 2.3- 0 \right )^{2}+\left ( 1.2-0 \right )^{2}}

d = 2.59 m

Thus, the distance between the origin and the point P is 2.59 m.

5 0
3 years ago
What happens when you see something?
Elan Coil [88]
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5 0
3 years ago
Select the correct answer from the drop-down menu. anne applies a force on a toy car and makes it move forward. what can be said
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Answer:

The forces could be gravity, friction between the car and the ground, the force Katie is applying and the normal reaction.

6 0
1 year ago
What is the (magnitude of the) centripetal acceleration (as a multiple of g=9.8~\mathrm{m/s^2}g=9.8 m/s ​2 ​​ ) towards the Eart
Wittaler [7]

Answer:

The centripetal acceleration as a multiple of g=9.8 m/s^{2} is 1.020x10^{-3}m/s^{2}

Explanation:

The centripetal acceleration is defined as:

a = \frac{v^{2}}{r}  (1)

Where v is the velocity and r is the radius

Since the person is standing in the Earth surfaces, their velocity will be the same of the Earth. That one can be determined by means of the orbital velocity:

v = \frac{2 \pi r}{T}  (2)

Where r is the radius and T is the period.

For this case the person is standing at a latitude 71.9^{\circ}. Remember that the latitude is given from the equator. The configuration of this system is shown in the image below.

It is necessary to use the radius at the latitude given. That radius can be found by means of trigonometric.

\cos \theta = \frac{adjacent}{hypotenuse}

\cos \theta = \frac{r_{71.9^{\circ}}}{r_{e}} (3)

Where r_{71.9^{\circ}} is the radius at the latitude of 71.9^{\circ} and r_{e} is the radius at the equator (6.37x10^{6}m).

r_{71.9^{\circ}} can be isolated from equation 3:

r_{71.9^{\circ}} = r_{e} \cos \theta  (4)

r_{71.9^{\circ}} = (6.37x10^{6}m) \cos (71.9^{\circ})

r_{71.9^{\circ}} = 1.97x10^{6} m

Then, equation 2 can be used

v = \frac{2 \pi (1.97x10^{6} m)}{24h}

Notice that the period is the time that the Earth takes to give a complete revolution (24 hours), this period will be expressed in seconds for a better representation of the velocity.

T = 24h . \frac{3600s}{1h} ⇒ 84600s

v = \frac{2 \pi (1.97x10^{6} m)}{84600s}

v = 146.31m/s

Finally, equation 1 can be used:

a = \frac{(146.31m/s)^{2}}{(1.97x10^{6}m)}

a = 0.010m/s^{2}

Hence, the centripetal acceleration is 0.010m/s^{2}

To given the centripetal acceleration as a multiple of g=9.8 m/s^{2}​ it is gotten:

\frac{0.010m/s^{2}}{9.8 m/s^{2}} = 1.020x10^{-3}m/s^{2}

6 0
3 years ago
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