Answer : The energy removed must be, 29.4 kJ
Explanation :
The process involved in this problem are :
![(1):C_6H_6(l)(322K)\rightarrow C_6H_6(l)(279K)\\\\(2):C_6H_6(l)(279K)\rightarrow C_6H_6(s)(279K)\\\\(3):C_6H_6(s)(279K)\rightarrow C_6H_6(s)(205K)](https://tex.z-dn.net/?f=%281%29%3AC_6H_6%28l%29%28322K%29%5Crightarrow%20C_6H_6%28l%29%28279K%29%5C%5C%5C%5C%282%29%3AC_6H_6%28l%29%28279K%29%5Crightarrow%20C_6H_6%28s%29%28279K%29%5C%5C%5C%5C%283%29%3AC_6H_6%28s%29%28279K%29%5Crightarrow%20C_6H_6%28s%29%28205K%29)
The expression used will be:
![Q=[m\times c_{p,l}\times (T_{final}-T_{initial})]+[m\times \Delta H_{fusion}]+[m\times c_{p,s}\times (T_{final}-T_{initial})]](https://tex.z-dn.net/?f=Q%3D%5Bm%5Ctimes%20c_%7Bp%2Cl%7D%5Ctimes%20%28T_%7Bfinal%7D-T_%7Binitial%7D%29%5D%2B%5Bm%5Ctimes%20%5CDelta%20H_%7Bfusion%7D%5D%2B%5Bm%5Ctimes%20c_%7Bp%2Cs%7D%5Ctimes%20%28T_%7Bfinal%7D-T_%7Binitial%7D%29%5D)
where,
= heat released for the reaction = ?
m = mass of benzene = 94.4 g
= specific heat of solid benzene = ![1.51J/g^oC=1.51J/g.K](https://tex.z-dn.net/?f=1.51J%2Fg%5EoC%3D1.51J%2Fg.K)
= specific heat of liquid benzene = ![1.73J/g^oC=1.73J/g.K](https://tex.z-dn.net/?f=1.73J%2Fg%5EoC%3D1.73J%2Fg.K)
= enthalpy change for fusion = ![-9.8kJ/mol=-\frac{9.8\times 1000J/mol}{78g/mol}=-125.6J/g](https://tex.z-dn.net/?f=-9.8kJ%2Fmol%3D-%5Cfrac%7B9.8%5Ctimes%201000J%2Fmol%7D%7B78g%2Fmol%7D%3D-125.6J%2Fg)
Now put all the given values in the above expression, we get:
![Q=[94.4g\times 1.73J/g.K\times (279-322)K]+[94.4g\times -125.6J/g]+[94.4g\times 1.51J/g.K\times (205-279)K]](https://tex.z-dn.net/?f=Q%3D%5B94.4g%5Ctimes%201.73J%2Fg.K%5Ctimes%20%28279-322%29K%5D%2B%5B94.4g%5Ctimes%20-125.6J%2Fg%5D%2B%5B94.4g%5Ctimes%201.51J%2Fg.K%5Ctimes%20%28205-279%29K%5D)
![Q=-29427.312J=-29.4kJ](https://tex.z-dn.net/?f=Q%3D-29427.312J%3D-29.4kJ)
Negative sign indicates that the heat is removed from the system.
Therefore, the energy removed must be, 29.4 kJ
Answer:
If the reaction requires energy, it is often indicated above the arrow. A capital Greek letter delta (Δ) is written on top of the reaction arrow to show that energy in the form of heat is added to the reaction; hv is written if the energy is added in the form of light.
690 Kelvin is the boiling point of this compound.
Explanation:
Enthalpy is the sum of internal energy and the product of pressure and volume that is how much energy is in the substance.
Entropy is the measurement of randomness and measure of thermal energy per unit of temperature.
ΔH vap of compound is 46.55 kJ⋅ mol− or J.MOL-1
ΔS vap is 67.37 J⋅mol−1⋅K−1.
The boiling point or temperature can be calculated by the formula:
T= ![\frac{ΔH vap}{ΔS vap}](https://tex.z-dn.net/?f=%5Cfrac%7B%CE%94H%20vap%7D%7B%CE%94S%20vap%7D)
T =
= 690 Kelvin
The boiling point is the temperature when atmospheric temperature gets equal to
your answer is C. considered a mixed success.