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Rudik [331]
3 years ago
7

A force of 7.50N is applied to a spring whose spring constant is 0.289 N/cm. Find its change in length.​

Physics
1 answer:
kotykmax [81]3 years ago
4 0

Hook's law states that

F=k\Delta x

where F is the applied force, k is the spring constant, and \Delta x is the change in length.

Plugging your values, we have

7.5 = 0.289\Delta x \implies \Delta x = \dfrac{7.5}{0.289}\approx 25.95

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Answer:

Energy cannot be changed from one form to another without a loss of usable energy

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Entropy of a system is given by heat absorbed divided by temperature. It is given by :

\Delta S=\dfrac{\Delta Q}{T}

So, the correct option is (A) "Energy cannot be changed from one form to another without a loss of usable energy".

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A certain spring has a spring constant k1 = 660 N/m as the spring is stretched from x = 0 to x1 = 35 cm. The spring constant the
pantera1 [17]

(a) The equation for the work done in stretching the spring from x1 to x2 is ¹/₂K₂Δx².

(b) The work done, in stretching the spring from x1 to x2 is 11.25 J.

(c) The work, necessary to stretch the spring from x = 0 to x3 is 64.28 J.

<h3>Work done in the spring</h3>

The work done in stretching the spring is calculated as follows;

W = ¹/₂kx²

W(1 to 2) = ¹/₂K₂Δx²

W(1 to 2)  =  ¹/₂(250)(0.65 - 0.35)²

W(1 to 2)  = 11.25 J

W(0  to 3) = ¹/₂k₁x₁² + ¹/₂k₂x₂² + ¹/₂F₃x₃

W(0  to 3) = ¹/₂(660)(0.35)² + ¹/₂(250)(0.65 - 0.35)² + ¹/₂(105)(0.89 - 0.65)

W(0  to 3) = 64.28 J

Learn more about work done here: brainly.com/question/25573309

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6 0
2 years ago
It takes a minimum distance of 76.50 m to stop a car moving at 15.0 m/s by applying the brakes (without locking the wheels). Ass
Vinvika [58]

The minimum stopping distance when the car is moving at 32.0 m/s is 348.3 m.

<h3>Acceleration of the car </h3>

The acceleration of the car before stopping at the given distance is calculated as follows;

v² = u² + 2as

when the car stops, v = 0

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<h3>Distance traveled when the speed is 32 m/s</h3>

If the same force is applied, then acceleration is constant.

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5 0
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