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Rudik [331]
4 years ago
7

A force of 7.50N is applied to a spring whose spring constant is 0.289 N/cm. Find its change in length.​

Physics
1 answer:
kotykmax [81]4 years ago
4 0

Hook's law states that

F=k\Delta x

where F is the applied force, k is the spring constant, and \Delta x is the change in length.

Plugging your values, we have

7.5 = 0.289\Delta x \implies \Delta x = \dfrac{7.5}{0.289}\approx 25.95

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