One strategy in a snowball fight is to throw

What happens to power as speed increases?

belka [17]

Well you know the formula is,

Power= Work/Time

So as time increases, Power Decreases, it's an inverse relationship.

Think about it like this, to have more "power" you have to be able to do a lot in a short amount of time, so by spending more time on something, your power decreases.

7 0

3 years ago

A motorcycle is moving at 18 m/s when its brakes are applied, bringing the cycle to rest in 4.7 s. To the nearest meter, how far

morpeh [17]

Answer:

the motorcycle travels 42.4 meters until it stops.

Explanation:

Vi= 18 m/s

Vf= 0 m/s

t= 4.7 sec

Vf= Vi - a*t

deceleration:

a= Vi/t

a= 18m/s / 4.7 sec => a=-3.82 m/s²

x= Vi*t - (a * t²)/2

x= 42.4m

4 0

3 years ago

If the load is 13 cm from the fulcrum, how much effort is needed to lifth the load ? Help me.

snow_tiger [21]

That depends on a few things that you haven't told us about the setup.
So I'm going to assume one of them, and then give you the answer
in terms of another one:

-- Assume a Class-I lever . . . the fulcrum is between the load and the effort.

-- Then the effort needed to lift the load is

(the weight of the load) x (13 / the distance between the fulcrum and the effort)

7 0

3 years ago

A particle moving at speed 0. 32 c has momentum p0. the speed of the particle is increased to 0. 72 c. what is its momentum now?

Semenov [28]

A particle moving at speed 0.32 c has momentum P₀. the speed of the particle is increased to 0.72 c then its momentum would be 2.25P₀.

<h3>What is momentum?</h3>

It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle, and the momentum of any particle is expressed in Kg m/s unit.

Mathematically the formula of the momentum is

P = mv

where P is the momentum of the particle

m is the mass of the particle

v is the velocity by which the particle is moving

As given in the question a particle moving at speed 0.32 c has momentum P₀. the speed of the particle is increased to 0.72 c

by using the formula of the momentum and substituting the values of the velocity

P =mv

As mentioned in the question when the particle is moving with 0.32c velocity it has a momentum of P₀

P₀ = m*(0.32c)

If the speed of the particle is increased to 0.72 c the momentum would be

P=m*(0.72c)

by dividing the second equation from the first one

P₀/P = 0.32c/0.72c

P₀/P = 0.44

P =2.25P₀

Thus, the increased momentum of the particle would be 2.25P₀

Learn more about momentum from here

brainly.com/question/17662202

#SPJ4

6 0

1 year ago

A produce distributor uses 800 packing crates a month, which it purchases at a cost of $10 each. The manager has assigned an ann

strojnjashka [21]

Answer:

$364.29

Explanation:

given,

Packing of crates per month (u)= 800

annual carrying cost of 35 percent of the purchase price per crate.

Ordering cost(S) = $ 28

D = 800 x 12 = 9600 crates/year

H = 0.35 P

H = 0.35 x $10

H = $3.50/crate per yr.

Present Total cost

= $\dfrac{800}{2}\times 3.50 + \dfrac{9600}{800}\times 28$

= 1400 + 336

= $ 1,736

$Q_0 = \sqrt{\dfrac{2DS}{H}}$

$Q_0 = \sqrt{\dfrac{2\times 9600 \times 28}{3.50}}$

$Q_0 =\$ 391.92$

Total cost at EOQ

= $\dfrac{391.92}{2}\times 3.50 + \dfrac{9600}{391.92}\times 28$

= 685.86 + 685.85

= $ 1,371.71

the firm save annually in ordering and carrying costs by using the EOQ

= $ 1,736 - $ 1,371.71

= $364.29

4 0

3 years ago