Simple Harmonic Motion Problems:

A student pulls a 2.0-kg object to the left with a force of 30 N, while another student is pulling against the object in the opp

alex41 [277]

Answer:

5 m/s2, left

Explanation:

We can solve the problem by applying Newton's second law of motion, which states that:

$\sum F=ma$

where:

$\sum F$ is the net force acting on an object

m is the mass of the object

a is its acceleration

In this problem, we have:

$\sum F=30 N - 20 N = 10 N$ (to the left) is the net force on the object

m = 2.0 kg is the mass

So, the acceleration is:

$a=\frac{\sum F}{m}=\frac{10}{2.0}=5.0 m/s^2$

in the same direction as the force (left).

5 0

3 years ago

Q11) If you were standing at the top of a building and you dropped a rock.

Dafna1 [17]

Answer:

Part A

The distance travel by the rock is approximately 132.496 m

Part B

The speed when the rock hits the ground is approximately 50.96 m/s

Explanation:

Part A

The question is focused on the kinetics equation of a free falling object

The given parameter is the time it takes the rock to hit the ground, t = 5.2 s

For an object in free fall, we have;

h = 1/2·g·t²

Where;

h = The height from which the object is dropped

g = The acceleration due to gravity ≈ 9.8 m/s²

t = The time taken to travel the distance, h = 5.2 s

∴ h = 1/2 × 9.8 m/s² × (5.2 s)² ≈ 132.496 m

The distance travel by the rock, h ≈ 132.496 m

Part B

The speed, 'v', when the rock hits the ground, is given by the following kinematic equation,

v = g·t

∴ v = 9.8 m/s² × 5.2 s = 50.96 m/s

The speed when the rock hits the ground, v ≈ 50.96 m/s.

8 0

2 years ago

A repelling force occurs between two charged objects when the charges are of Equal magnitude. Equal magnitude. a Unequal magnitu

Ahat [919]

Answer:

c Like/same signs

Explanation:

A repelling force occurs between two or more charged objects with the charges are of like or same sign.

According to Coulombs law, like charges repel on another, unlike charges attracts on another.
If a positive charge comes into the vicinity of another positive charge, there will be repulsion.
When oppositely charge species are brought near each other, there is an attraction.

Therefore, repulsion occurs when like charges are brought close to each other.

3 0

2 years ago

What is the law of variation of the period T of a simple pendulum

DIA [1.3K]

The period of a simple pendulum is given by:
$T=2 \pi \sqrt{ \frac{L}{g} }$
where L is the length of the pendulum and $g=9.81 m/s^2$ is the gravitational acceleration. As we can see, the period of a simple pendulum depends only on its length.

3 0

3 years ago

Initially (at time t = 0) a particle is moving vertically at 7.5 m/s and horizontally at 0 m/s. Its horizontal acceleration is 1

Lelu [443]

Answer:

t = 0.657 s

Explanation:

given,

initial vertical velocity = 7.5 m/s

initial horizontal velocity = 0 m/s

angle = 49◦

using kinetic equation

final velocity in vertical direction

v sinθ = u_y - gt ........................(1)

final velocity in horizontal direction

v cosθ = u_x + a_x × t

here u_x = 0.0 m/s

v cosθ = a_x×t ......................(2)

Dividing equation (1) / (2)

$tan \theta =\dfrac{u_y - gt}{a_x\times t}$

solving for time t

$t = \dfrac{u_y}{tan \theta \times a_x + g}$

u_y = initial velocity along x direction

acceleration along a_x = 1.4 m/s²

g = acceleration due to gravity = 9.8 m/s²

θ = 43° , u_y = 7.5 m/s

$t = \dfrac{7.5}{tan 49^0\times 1.4+ 9.8}$

t = 0.657 s

time taken by the particle is t = 0.657 s

6 0

3 years ago