Answer:
The magnitude of the centripetal force to make the turn is 3,840 N.
Explanation:
Given;
radius of the cured road, r = 400 m
speed of the car, v = 32 m/s
mass of the car, m = 1500 kg
The magnitude of the centripetal force to make the turn is given as;
where;
Fc is the centripetal force
Therefore, the magnitude of the centripetal force to make the turn is 3,840 N.
Answer:
Alice Distance = 100 meters
Peter's Distance = 3 km
Alice Displacement and Peter's displacement are both 100 meters upwards.
Explanation:
To solve this question, we have to first define distance and displacement.
Distance is simply the measurement of the sum of all paths travelled from one point to another while displacement is measurement of the shortest distance from initial point to final point.
Now, Alice and Peter are moving from the same point.
Alice distance travelled is 100 meters.
Also, her displacement will be 100 meters because it is the shortest distance to the summit of the cliff.
Now, for Peter, he decides to take a longer route which is 3 km in distance.
However, the shortest path which is the displacement is still 100 meters.
Thus, Peter's displacement is 100 meters.
Well, I guess you can come close, but you can't tell exactly.
It must be presumed that the seagull was flying through the air
when it "let fly" so to speak, so the jettisoned load of ballast
of which the bird unburdened itself had some initial horizontal
velocity.
That impact velocity of 98.5 m/s is actually the resultant of
the horizontal component ... unchanged since the package
was dispatched ... and the vertical component, which grew
all the way down in accordance with the behavior of gravity.
98.5 m/s = √ [ (horizontal component)² + (vertical component)² ].
The vertical component is easy; that's (9.8 m/s²) x (drop time).
Since we're looking for the altitude of launch, we can use the
formula for 'free-fall distance' as a function of acceleration and
time:
Height = (1/2) (acceleration) (time²) .
If the impact velocity were comprised solely of its vertical
component, then the solution to the problem would be a
piece-o-cake.
Time = (98.5 m/s) / (9.81 m/s²) = 10.04 seconds
whence
Height = (1/2) (9.81) (10.04)²
= (4.905 m/s²) x (100.8 sec²) = 494.43 meters.
As noted, this solution applies only if the gull were hovering with
no horizontal velocity, taking careful aim, and with malice in its
primitive brain, launching a remote attack on the rich American.
If the gull was flying at the time ... a reasonable assumption ... then
some part of the impact velocity was a horizontal component. That
implies that the vertical component is something less than 98.5 m/s,
and that the attack was launched from an altitude less than 494 m.
The magnetic part using the Lorentz force is: F = q v x
B,
where v and B are vectors and v x B is the vector cross product.
Magnitude of the force: F = q v B sin(α)
So, sin(α) = F/( e v B), with e the proton charge.
This will give you a value for sin(α), and two potentials
for its opposite.
You will now look for:
sin(α) = 7.40 10^-13/( 1.60 10^-19 * 5 10^6 * 1.78)
= 0.520
So either sin(α) = 0.502 or sin(α) = -0.502
The 1st α = 30.1 degrees or α = 150 degrees.
The 2nd α = 210 degrees or α = 330 degrees.
So we can say that 30.1 degrees and 330 degrees would be minimum and biggest on [0,360]
Our planet is closed system because there is a limit of how much matter could be exchanged.
