Alexis is a scientist who is studying solid-state physics. Which activity would she most likely do as a part of this research? O
1 answer:
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Answer:
Width of sound beam is 7.557 m
Explanation:
First we will calculate the wave length from given data:
λ=v/f
Were:
v is the speed
f is the frequency
We considered the opening long and narrow, Using single slit diffraction formula:
mλ=dsinΘ
where:
d is the crack width
m is the order
Θ is angle
Considering m=1, The angle between first minimum from center of beam is:
The width of beam is:
tanΘ=y/L
Width=7.557 m
(a) If a source emits sound of wavelengths 2. 64 m and 2. 72 m in air, 4 beats per second will be heard.
(b)The maximum intensity regions are apart by 90 m (approx).
Given,
Wavelengths of sound waves emitted by the source are respectively = 2.64 m and λ2 = 2.72 m
(a) As the measurement of the beats per second is equal to the frequency difference of the overlapping two sound waves,
Therefore, the frequency difference of the two waves is,
Δf =()
where and
are the frequencies of waves of wavelength λ1 and λ2
Now, speed of sound in air at temperature t = 20° C, is v = 343 m/s
∴ Δf = ()
⇒Δf =
⇒Δf =
⇒Δf ≅ 4
Hence 4 beats per second will be heard.
(b) When two waves overlap in the same phase in a region the intensity of that region becomes maximum due to constructive interference.
For constructive interference, the path difference is = nλ
Therefore the difference between the maximum intensity regions is given by,
d =
⇒d≅90 m
Hence the maximum intensity regions are apart by 90 m (approx).
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