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Tatiana [17]
3 years ago
5

Rob is studying for an exam. He listed some properties of magnets in a Maglev train.

Physics
2 answers:
fredd [130]3 years ago
7 0
The answer is the third one. Maglev is short for Magnetic Levitation in which trains skim on a guideway utilizing the guideline of attractive shock. Every magnet has two shafts. Presently in the event that you play with two magnets, you'll understand that inverse shafts pull in, though comparable posts repulse. This shocking property of magnets is utilized as a part of Maglev trains. However,instead of utilizing lasting magnets, the standard of electromagnetism is utilized to make solid and huge impermanent magnets. At the point when an electric current is gone through a loop of wire, attractive field is created around the curl as indicated by Faraday's laws.
inn [45]3 years ago
5 0

Answer:

D. The repelling of the support magnet decreases friction.

The magnets are repelling, so they are not directly touching. This allows for decreased friction.

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2. We know that the Earth is moving around the sun. When we look at the sky we see
marin [14]

Answer:

Answer: The Sun, the Moon, the planets, and the stars all rise in the east and set in the west. And that's because Earth spins -- toward the east. ... Earth rotates or spins toward the east, and that's why the Sun, Moon, planets, and stars all rise in the east and make their way westward across the sky.

6 0
3 years ago
How does the angle of launch affect the kinetic energy of a rubber band?​
Lady_Fox [76]

Answer:

The angle of launch of the rubber band affects the initial velocity. The more the rubber band is stretched the more force it applies to return to equilibrium and the more kinetic energy that results in.

3 0
3 years ago
Consider the free-body diagram. If you want the box to move, the force applied while dragging must be greater than the
VLD [36.1K]

You would want it to be greater than D. friction force

It needs be greater than the friction applied to it.

6 0
3 years ago
Which row shows what happens to the temperature of a solid as it melts and what happens to the temperature when
frez [133]

When ice melts, its temperature doesn't change ... ice at 32 degrees becomes water at 32 degrees.

When water boils, its temperature doesn't change ... water at 212 degrees becomes steam at 212 degrees.

The row that says both of these is row-D .

4 0
3 years ago
Two astronauts, each with a mass of 50 kg, are connected by a 7 m massless rope. Initially they are rotating around their center
kiruha [24]

Answer:

The angular  velocity is w_f =  1.531 \ rad/ s

Explanation:

From the question we are told that

     The mass of each astronauts is  m =  50 \ kg

      The initial  distance between the two  astronauts  d_i  =  7 \  m

Generally the radius is mathematically represented as r_i  =  \frac{d_i}{2} = \frac{7}{2}  =  3.5 \  m

      The initial  angular velocity is  w_1 = 0.5 \  rad /s

       The  distance between the two astronauts after the rope is pulled is d_f =  4 \  m

Generally the radius is mathematically represented as r_f  =  \frac{d_f}{2} = \frac{4}{2}  =  2\  m

Generally from the law of angular momentum conservation we have that

           I_{k_1} w_{k_1}+ I_{p_1} w_{p_1} = I_{k_2} w_{k_2}+ I_{p_2} w_{p_2}

Here I_{k_1 } is the initial moment of inertia of the first astronauts which is equal to I_{p_1} the initial moment of inertia of the second astronauts  So

      I_{k_1} = I_{p_1 } =  m *  r_i^2

Also   w_{k_1 } is the initial angular velocity of the first astronauts which is equal to w_{p_1} the initial angular velocity of the second astronauts  So

      w_{k_1} =w_{p_1 } = w_1

Here I_{k_2 } is the final moment of inertia of the first astronauts which is equal to I_{p_2} the final moment of inertia of the second astronauts  So

      I_{k_2} = I_{p_2} =  m *  r_f^2

Also   w_{k_2 } is the final angular velocity of the first astronauts which is equal to w_{p_2} the  final angular velocity of the second astronauts  So

      w_{k_2} =w_{p_2 } = w_2

So

      mr_i^2 w_1 + mr_i^2 w_1 = mr_f^2 w_2 + mr_f^2 w_2

=>   2 mr_i^2 w_1 = 2 mr_f^2 w_2

=>   w_f =  \frac{2 * m * r_i^2 w_1}{2 * m *  r_f^2 }

=>    w_f =  \frac{3.5^2 *  0.5}{  2^2 }

=>   w_f =  1.531 \ rad/ s

       

3 0
3 years ago
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