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enot [183]
3 years ago
14

Cora, an electrician, wraps a copper wire with a thick plastic coating. What is she most likely trying to do? keep the electric

potential of the wire balanced decrease the wire’s resistance increase the voltage produced by the wire keep a current from passing out of the wire
Chemistry
2 answers:
MaRussiya [10]3 years ago
4 0

Answer:

D

Explanation:

Alekssandra [29.7K]3 years ago
3 0

Answer: keep a current from passing out of the wire

Explanation: plastic is an insulator and will not conduct electricity

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___AsCl3+____H2S-->___As2S3+___HCI​
Alex17521 [72]

Answer:

2 AsCl₃ + 3 H₂S → As₂S₃ + 6 HCl

Explanation:

When we balance a chemical equation, what we are trying to do is to achieve the same number of atoms for each element on both sides of the arrow. On the right of the arrow is where we can find the products, while the reactants are found on the left of the arrow.

We usually balance O and H atoms last.

AsCl₃ + H₂S → As₂S₃ +HCl

<u>reactants</u>

As --- 1

Cl --- 3

H --- 2

S --- 1

<u>products</u>

As --- 2

Cl --- 1

H --- 1

S --- 3

2 AsCl₃ + H₂S → As₂S₃ +HCl

<u>reactants</u>

As --- 2

Cl --- 6

H --- 2

S --- 1

<u>products</u>

As --- 2

Cl --- 1

H --- 1

S --- 3

The number of As atoms is now balanced.

2 AsCl₃ + 3 H₂S → As₂S₃ +HCl

<u>reactants</u>

As --- 2

Cl --- 6

H --- 6

S --- 3

<u>products</u>

As --- 2

Cl --- 1

H --- 1

S --- 3

The number of S atoms is now equal on both sides.

2 AsCl₃ + 3 H₂S → As₂S₃ + 6 HCl

<u>reactants</u>

As --- 2

Cl --- 6

H --- 6

S --- 3

<u>products</u>

As --- 2

Cl --- 6

H --- 6

S --- 3

The equation is now balanced.

3 0
2 years ago
I have two solutions. In the first solution, 1.0 moles of sodium chloride is dissolved to make 1.0 liters of solution. In the se
charle [14.2K]

i not sure but I think yes

6 0
3 years ago
1.Which form of energy is due to the motion of an object's particles .
tamaranim1 [39]

Answer:

thermal

Explanation:

4 0
3 years ago
WILL MARK BRAINLIEST!!
frozen [14]

Answer:

Na 1s2 2s2 2p6 3s1

Ar 1s2 2s2 2p6 3s2 3p6

Explanation:

7 0
3 years ago
What is the volume occupied by 2.50 moles of oxygen gas at STP
oee [108]
1 mole of any gas  under STP has volume 22.4 L
So 2.50 moles of any gas ( including oxygen)
2.50 mol *(22.4L/1 mol)=56.0 L
8 0
3 years ago
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