-- Equations #2 and #6 are both the same equation,
and are both correct.
-- If you divide each side by 'wavelength', you get Equation #4,
which is also correct.
-- If you divide each side by 'frequency', you get Equation #3,
which is also correct.
With some work, you can rearrange this one and use it to calculate
frequency.
Summary:
-- Equations #2, #3, #4, and #6 are all correct statements,
and can be used to find frequency.
-- Equations #1 and #5 are incorrect statements.
When balanced forces act on an object at rest, the object will not move. If you push against a wall, the wall pushes back with an equal but opposite force. Neither you nor the wall will move. Forces that cause a change in the motion of an object are unbalanced forces.
Answer:
increases by a factor of 
Explanation:
First we need to find the initial velocity for it to stop at the distance 2d using the following equation of motion:
where v = 0 m/s is the final velocity of the package when it stops, 
is the initial velocity of the package when it, a is the deceleration, and 
is the distance traveled.
So the equation above can be simplified and plug in Δs = d, 
for the 1st case
(1)
For the 2nd scenario where the ramp is changed and distance becomes 2d, 
(2)
let equation (2) divided by (1) we have:
So the initial speed increases by . If the deceleration a stays the same and time is the ratio of speed over acceleration a
The time would increase by a factor of
(a) By definition of average acceleration,
<em>a</em> = ∆<em>v</em> / ∆<em>t</em> = (0 - 38 m/s) / (5.0 s)
<em>a</em> = -7.6 m/s²
(b) Recall that
<em>v</em>² - <em>u</em>² = 2 <em>a</em> ∆<em>x</em>
where <em>u</em> and <em>v</em> are initial and final velocities, respectively; <em>a</em> is acceleration; and ∆<em>x</em> is the change in position. So
0² - (38 m/s)² = 2 (-7.6 m/s²) ∆<em>x</em>
∆<em>x</em> = 95 m
Answer: 
Explanation:
Firstly, let's convert these length to meters 
, in order to work with the same units:
a. 400 millimeters
b. 22 kilometers
c. 170 meters
Here the lenght is already in meters
d. 3.3 centimeters
Now that we have all the lengths in meters, we can order them from shortest to longest:
or
