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Vanyuwa [196]
4 years ago
15

Ce cantitate de O se gaseste in 5,8 g hidroxid de magneziu

Chemistry
1 answer:
coldgirl [10]4 years ago
4 0

Answer:

separare pâlnii de picurare balon cotat. 1. 2. 3. 4 5 6 7. 8. 9. 1 ... Mod de lucru: 25 g Na2SO4∙7H2O se dizolvă în cantitatea minim ... Exemple: NaOH – hidroxid de sodiu.

Explanation:

make me as brain liest

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Which is the chemical formula for a dinitrogen trioxide molecule?
Veseljchak [2.6K]

Answer:

The Answer would be D. N2O3

Explanation:

the Chemical bond is a Covalent bond to which the prefixes are Di and tri

8 0
3 years ago
For isoelectronic ions, how are effective nuclear charge and ionic radius related?
photoshop1234 [79]
For isoelectronic ions, as nuclear charge increases, effective nuclear charge increases and ionic radius decreases.
8 0
3 years ago
Read 2 more answers
Enter your answer in the provided box.The equilibrium constant Kc for the equation2H2(g) + CO(g) ⇌ CH3OH(g)is 35 at a certain te
Sphinxa [80]

Answer:

The concentration of CO is 4.33*10⁻³\frac{moles}{L}

Explanation:

A reversible chemical reaction, as in this case, occurs in both directions: reagents transforming into products (direct reaction) and products transforming back into reagents (reverse reaction).

Chemical Equilibrium is the state in which the direct and indirect reaction have the same reaction rate and is defined by a chemical constant Kc.

Being:

aA + bB ⇔ cC + dD

where A, B, C and D represent the chemical species involved and a, b, c and d their respective stoichiometric coefficients, constant Kc is defined as:

Kc=\frac{[C]^{c}*[D]^{d}  }{[A]^{a} *[B]^{b} }

In the case of the reaction

2 H₂(g) + CO(g) ⇌ CH₃OH(g)

the equilibrium constant Kc is:

Kc=\frac{[CH_{3}OH] }{[H_{2} ]^{2}*[CO] }

You know:

  • Kc=35
  • [CH₃OH] =\frac{4.87*10^{-3}moles }{3.63 L} =1.34*10^{-3} \frac{moles}{L}
  • [H₂]=\frac{3.21*10^{-2}moles }{3.63 L} =8.84*10^{-3} \frac{moles}{L}
  • [CO]=?

Replacing:

35=\frac{1.34*10^{-3} }{(8.84*10^{-3} )^{2} *[CO]}

Solving you get:

[CO]= \frac{1.34*10^{-3} }{(8.84*10^{-3} )^{2} *35}

[CO]=4.33*10⁻³\frac{moles}{L}

<u><em>The concentration of CO is 4.33*10⁻³</em></u>\frac{moles}{L}<u><em /></u>

8 0
4 years ago
How does a combustion reaction differ from other types of chemical reactions?
Molodets [167]
Unlike other reactions, combustion requires oxygen in order to occur.
This means that oxygen is a necessary condition for any combustion reaction to occur.

Based on the above, the difference between combustion reaction and other reactions is:
- It requires oxygen as an input or a medium to occur in

Hope this helps :)


5 0
3 years ago
How many carbon dioxide molecules must be added to rubp to make a single molecule of glucose?
Pani-rosa [81]

Answer:

6 carbon dioxide molecules

Explanation:

The Calvin cycle generates the necessary reactions for the fixation of carbon in a solid structure for the formation of glucose and, in turn, regenerates the molecules for the continuation of the cycle.

The Calvin cycle is also known as the dark phase of photosynthesis or also called the carbon fixation phase. It is known as the dark phase because it is not light dependent as is the first phase or light phase .

This second stage of photosynthesis fixes the carbon of the absorbed carbon dioxide and generates the precise number of biochemical elements and processes necessary to produce sugar and recycle the remaining material for continuous production.

The Calvin cycle uses the energy produced in the light phase of photosynthesis to fix the carbon dioxide (CO2) carbon in a solid structure such as glucose, in order to generate energy.

The glucose molecule composed of a six-carbon main structure will be further processed in glycolysis for the preparatory phase of the Krebs cycle, both part of the cellular respiration.

The Calvin cycle produces in six turns a six-carbon glucose molecule and regenerates three RuBP that will be catalyzed again by the RuBisCo enzyme with CO2 molecules for the restart of the Calvin cycle.

The Calvin cycle requires six molecules of CO2, 18 ATP and 12 NADPH produced in the light phase of photosynthesis to produce a glucose molecule and regenerate three RuBP molecules.

7 0
3 years ago
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