The concentration of the HCl solution is 0.72 M.
<h3>How do we calculate the concentration?</h3>
Concentration of the required solution by the use of the known concentration solution will be determine by using the below equation as:
M₁V₁ = M₂V₂, where
- M₁ & V₁ are the molarity and volume of the HCl solution.
- M₂ & V₂ are the molarity and volume of the NaOH solution.
On putting values in the above equation, we get
M₁ = (1)(0.018) / (0.025) = 0.72 M
Hence required concentration of HCl is 0.72M.
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1) Write the balaced chemical equation:
H2 + 2O2 → 2H2O
2) Infere the molar ratios:
1 mol H2 : 2 mol of water
3) Make the calculus as the direct proportion relation:
[2 mol H2O] / [1 mol H2] * 7 mol H2 = 14 mol H2
As you see you produce the double number of moles of H2O than number of moles of H2 used.
Answer: 14 moles
Answer:
72
Explanation:
The pattern here may be hard to find at first, but it's this: the number in the middle of the triangle = (number at lower left corner of triangle x number at upper vertex of triangle) + (number at upper vertex of triangle x number at lower right corner of triangle).
Thus, for the missing value...
Missing value = (3x8) + (8x6) = 24+48 = 72.
Could you tell me what concept in chemistry relates to this? I'm interested.
Also check out stylesben's answer. Seems like there's several ways of doing this.
Its condensation
the vapour has a lot of kinetic energy but if it cools down it loses that energy and condenses into a liquid
hope that helps
