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Valentin [98]
3 years ago
14

A sample of an ideal gas at 1.00 atm and a volume of 1.73 L was placed in a weighted balloon and dropped into the ocean. As the

sample descended, the water pressure compressed the balloon and reduced its volume. When the pressure had increased to 70.0 atm, what was the volume of the sample
Chemistry
1 answer:
kolezko [41]3 years ago
7 0

Answer:

Volume is 0.0247L

Explanation:

This question involves the use of Boyle's law which states that the volume of a given mass of gas is inversely proportional to it's pressure provided that temperature remains constant.

Mathematically,

v = k/p

K = VP

P1V1 = P2V2 = P3V3 = .........=PnVn

V = volume

p = pressure

Data;

P1 =1.0atm

V1 = 1.73L

P2 = 70atm

V2 = ?

P1V1 = P2V2

V2 = P1V1 / P2

V2 = (1.0×1.73)/70

V2 = 0.0247L

The volume of the sample is 0.0247L

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At a certain temperature the vapor pressure of pure acetic acid HCH3CO2 is measured to be 226.torr. Suppose a solution is prepar
Rudiy27

Answer:

The partial pressure of acetic acid is 73.5 torr

Explanation:

Step 1: Data given

Total pressure is 226 torr

mass of acetic acid = 126 grams

mass of methanol = 141 grams

 

Step 2: Calculate moles of acetic acid

moles acetic acid = mass acetic acid / molar mass acetic acid

moles acetic acid = 127 grams / 60.05 g/mol

moles acetic acid = 2.115 moles

Step 3: Calculate moles of methanol

moles methanol = 141 grams / 32.04 g/mol

moles methanol = 4.40 moles

Step 4: Calculate total moles

Total moles = moles of acetic acid + moles methanol

Total moles = 2.115 moles + 4.40 moles

Total moles = 6.515 moles

Step 5: Calculate mole fraction of acetic acid

2.115 moles / 6.515 moles = 0.325

Step 6: Calculate partial pressure of acetic acid

P(acetic acid) = 0.325 * 226

P(acetic acid) = 73.45 torr ≈73.5

 

We can control this by calculating the partial pressure of methanol

mole fraction of methanol = (6.515-2.115)/6.515 = 0.675

P(methanol) = 0.675 * 226 = 152.55

226 - 152.55 = 73.45 torr  

The partial pressure of acetic acid is 73.5 torr

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