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Naddik [55]
3 years ago
6

write the ground-state electron configurations of the seventh and eighth elements in the first transition series in Universe fif

th transition metal: sixth transition metal:
Chemistry
1 answer:
Tju [1.3M]3 years ago
5 0

Answer: Check explanation.

Explanation:

Transition metals are metallic elements that can be found in the Groups IVB–VIII, IB, and IIB on the periodic chart.

The question require us to write down the GROUND state electronic configuration of the first fifth transition metal, sixth transition metal, seventh transition metal element and the eighth transition metal.

NOTE: we are Starting from Argon, which has 18 electrons.

The fifth transition metal is Manganese,Mn. Manganese has 25 electrons, that is, 25- 18= 7. Therefore, it needs seven electrons to complete the configuration.

Hence, The ground state electronic configuration = [Ar)] 3d5. 4s2.

The first sixth Transition metal is iron,Fe. Iron has 26 electrons, that is, 26 - 18 = 8. Therefore, it need eight Electrons to complete the ground state electronic configuration.

Hence, the ground state electronic configuration of Fe= [Ar] 3d6. 4s2.

The first seventh transition metal is Cobalt, Co. It has 27 Electrons, therefore, 27- 18 = 9. Therefore, it needs 9 Electrons to complete its ground state electronic configuration.

Ground state electronic configuration of Co= [Ar] 3d7. 4s2.

The first eight Transition metal is Nickel. It has 28 electrons. Therefore, 28-18= 10. So, it needs 10 Electrons to complete its ground state electronic configuration.

Hence, the Ground state electronic configuration of Ni= [Ar] 3d8. 4s2.

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Find the percent composition of lead in lead (II) nitrate. round to 2 significant figures.​
just olya [345]

Answer/Explanation:

62.559%

mass of an element   X 100%

mass of the compound

Scientific Notation: 3.45 x 10^5

E Notation: 3.45e5

5 0
3 years ago
For the reaction shown, identify the element oxidized, the element reduced, the oxidizing agent, and the reducing agent. KNO3 →
Vinvika [58]

Answer : The oxidizing element is N and reducing element is O. 

KNO_{3} is act as an oxidizing agent as well as reducing agent.

Explanation :

An Oxidizing agent is the agent which has ability to oxidize other or a higher in oxidation number.

Reducing agent is the agent which has ability to reduce other or lower in oxidation number.

The given reaction is :

KNO_{3} \rightarrow KNO_{2} +O_{2}

KNO_{3}  act as an oxidizing agent.

The oxidation number of N in KNO_{3} is calculated as:

(+1)+(x)+3(-2) = 0

x = +5

And the oxidation number of N in KNO_{2}  is calculated as:

(+1)+(x)+2(-2) = 0

x = +3

From the oxidation number method, we conclude that the oxidation number  reduced this means KNO_{3} itself get reduced to KNO_{2} and it can act as an oxidizing agent.

KNO_{3}  act as a reducing agent.

KNO_{3} \rightarrow KNO_{2} +O_{2}

The oxidation number of O in KNO_{3} is calculated as:

(+1)+(+5)+3(x) = 0

x = -2

The oxidation number of O in O_{2} is Zero (o).

Now, we conclude that the oxidation number increases this means KNO_{3} itself get oxidized to O_{2} and it can act as reducing agent.





                     

4 0
4 years ago
Read 2 more answers
BF3 type of compound
USPshnik [31]

Answer:

Corresponds to a covalent compound.

Explanation:

Both Boron and Fluorine are nonmetals, forming a covalent bond, the result of which is the boron trifluoride compound (BF3). This is a highly toxic gas.

It is synthesized by the reaction between hydrogen fluoride and boron oxide:

B2O3 + 6 HF → 2 BF3 + 3 H2O

6 0
3 years ago
A gas occupies 10.2 liters at 0.60 atm. What is the pressure if the volume becomes 3.0 L?
Arturiano [62]
P1V1 = P2V2
P1 = 0.60 atm
V1 = 10.2 L
P2 = ?
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Solve for P2 —> P2 = P1V1/V2 = (0.60 atm)(10.2 L) / (3.0 L) = 2.04 atm
3 0
3 years ago
When she placed her hand on the side of the container, it felt really cold, but it didn't feel that way before. The temperature
artcher [175]

Answer:

this is a physical reaction

Explanation:

3 0
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