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2 years ago

Which of the following trends is indirectly proportional to effective nuclear charge, Zeff

Chemistry

2 answers:

Julli [10]2 years ago

7 0

Answer : Option C) Atomic Size

Explanation : The atomic radius of the elements is found to be decreasing if we go from left to right in the modern periodic table. Accordingly, $Z_{eff}$ increases as the number of shielding electrons present in the atomic nucleus of the periodic elements which lies in the same row remains constant while the number of protons in each atomic shell increases.

The effective nuclear charge $Z_{eff}$ of an atom is defined as the net positive charge which is felt by the valence electron of the atomic element.

When $Z_{eff}$ is observed to decrease, it is seen that the atomic radius grows in size. So, it explains the inverse relationship between both. This phenomenon occurs, because there is more screening of the electrons from the nucleus taking place, which is observed due to decrease the attraction between the electron and the nucleus.

ra1l [238]2 years ago

3 0

Periodic trends provides information about an element’s properties. One major trends in the periodic table is the atomic size, which is indirectly proportional to effective nuclear charge. The atomic size gradually decreases from left to right across a periodic table because all electrons are added to the same shell. At the same time, protons are also added to the nucleus, making it more positively charged.

Due to this, there is a greater nuclear attraction; the effect of increasing proton number is greater than that of the increasing electron number, which means that there is a strong attraction of nucleus manifested by pulling the atom's shell closer to the nucleus. Then, the valence electrons are seized closer towards the nucleus of the atom, which resulted to the decrease in atomic radius.

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Calculate the cfse for a d^3 system in an octahedral field in units of ∆_o. In other words, do not enter "∆_o" with your answer.

Rudik [331]

Magnetic moment (spin only) of octahedral complex having CFSE=−0.8Δo and surrounded by weak field ligands can be : Q

To answer this, the Crystal Field Stabilization Energy has to be calculated for a (d3 metal in both configurations. The geometry with the greater stabilization will be the preferred geometry. So for tetrahedral d3, the Crystal Field Stabilization Energy is: CFSE = -0.8 x 4/9 Δo = -0.355 Δo.

[Co(CN)64-] is also an octahedral d7 complex but it contains CN-, a strong field ligand. Its orbital occupancy is (t2g)6(eg)1 and it therefore has one unpaired electron. In this case the CFSE is −(6)(25)ΔO+(1)(35)ΔO+P=−95ΔO+P.

The crystal field stabilization energy (CFSE) (in kJ/mol) for complex, [Ti(H2O)6]3+. According to CFT, the first absorption maximum is obtained at 20,3000cm−1 for the transition.

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3 months ago

If a 2.50 liter container is filled with Ne gas at a pressure of 650 mm Hg and at 25°C, what mass of Ne is in the container?

seraphim [82]

Answer:

1.76 g is the mass of Ne is in the container.

Explanation:

We use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of the gas = 650 mm Hg

V = Volume of the gas = 2.50 L

T = Temperature of the gas = $25^oC=[25+273]K=298K$

R = Gas constant = $62.3637\text{ L.mmHg }mol^{-1}K^{-1}$

n = number of moles of Ne gas = ?

Putting values in above equation, we get:

$650mmHg\times 2.50L=n\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 298K\\\\n=\frac{650\times 2.50}{62.3637\times 298}=0.0874mol$

Also, molar mass of Ne = 20.1797 g/mol

So, $Mass = Moles\times Molar\ mass = 0.0874\times 20.1797 g = 1.76\ g$

<u>1.76 g is the mass of Ne is in the container.</u>

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2 years ago

How many significant figures does 0.040040 have ?

Georgia [21]

Answer: 2 is the answer

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2 years ago

Which best evaluates the following statement: It's greener to wash dishes by hand than to use a dishwasher?

Volgvan

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3 0

2 years ago

During your reaction, you added 0.3 mL concentrated H2SO4 (18.4 M) as the catalyst. At the end of the reaction, you need to add

sattari [20]

Answer:

58.72 mL

Explanation:

The chemical equation for the neutralization reaction is :

H₂SO₄(aq) + Na₂CO₃(s) --------------> Na₂SO₄(aq) + H₂O(l) + CO₂(g)

where;

M₁ = Molarity of H₂SO₄

M₂= Molarity of Na₂CO₃

V₁= Volume of H₂SO₄

V₂ = Volume of Na₂CO₃

Given that :

M₁ = 18.4 M

V₁= 0.3 mL

10% Na₂CO₃ means 100 g of solution contain 10 g of Na₂CO₃

i.e. 10 g Na₂CO₃ dissolved and diluted to 100 mL water.

Molar mass of Na₂CO₃ = 106 g/mol

106 g Na₂CO₃ dissolved in 100 mL will give 0.1 M Na₂CO₃ solution.

However;

If, 106 g Na₂CO₃ ≡ 0.1 M Na₂CO₃

Then, 10 g Na₂CO₃ ≡ 'A' M of Na₂CO₃

By cross multiplying; we have:

106 × A = 10 × 0.1

106 × A = 1

A = (1/106) M/100 mL

A = 10 x (1/106)) M/L

A = (10/106) M

A = 0.094 M

Therefore,the molarity of 10% Na₂CO₃ solution is 0.094 M.

For the Neutralization equation, we have:

M₁V₁ = M₂V₂

18.4×0.3 = 0.094×V₂

Making V₂ the subject of the formula;we have:

$V_2 = \frac{18.4*0.3}{0.094}$

V₂ = 58.72 mL

4 0

2 years ago