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Sliva [168]
3 years ago
9

Are passing through optical Centre deviate why ​

Physics
1 answer:
nikklg [1K]3 years ago
7 0

Answer:

Actually the same happens when the ray passes through optical centre. This can be observed in a thick lens. In thin lenses the perpendicular distance between extended incident ray and extended emergent ray is negligible. So we can say that light ray passes through optical centre without deviation.

Explanation:

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A small object carrying a charge of -3.00 nc is acted upon by a downward force of 30.0 nn when placed at a certain point in an e
arlik [135]
The working equation for this one is:

E = F/Q, where E is the strength of the electric field, F is the electric force and Q is the charge. Substituting the corresponding values, the strength of the electric field is equal to

E = -30 nN/-3 nC
E = 10 nN/nC


3 0
4 years ago
Pls,help ASAP .the question is in attachment​
Alex777 [14]

Answer:c

Explanation:

8 0
3 years ago
If the frequencies of two component waves are 24 Hz and 20 Hz, they should produce _______ beats per second.
horrorfan [7]
This can be answered using the beat frequency formula, which is simply the difference between 2 frequencies.

Let: <span>fᵇ = beat frequency
</span>f₁ = first frequency
f₂ = second frequency

fᵇ = |f₁ - f₂|

substituting the values:
fᵇ = |24Hz - 20Hz|
fᵇ = 4Hz

The unit Hz also means beats per second, therefore:
<span>fᵇ = 4 beats per second
</span>
Therefore, the answer is C. 4
8 0
4 years ago
Read 2 more answers
If the refractive index of a medium is 1.3,
Nataly [62]

Explanation:

see the above attachment to solve the question and get the answer.

hope this helps you.

3 0
3 years ago
Read 2 more answers
How much heat Q H QH does a heat pump with a coefficient of performance of 2.10 2.10 deliver when supplied with 1.82 kJ 1.82 kJ
valina [46]

The operating coefficient or performance coefficient of a heat pump is the ratio between the heating or cooling provided and the electricity consumed. The higher coefficients are equivalent to lower operating costs. The coefficient can be greater than 1, because it is a percentage of the output: losses, other than the thermal efficiency ratio: input energy. Mathematically can be written as,

\text{Coefficient of performance} = \frac{\text{Heat extracted}}{\text{Electrical energy supplied}}

COP = \frac{Q}{E}\rightarrow Q =COP\times E

Replacing,

Q = 2.1\times 1.82kJ

Q = 3.822kJ

Therefore the heat is 3.822kJ

4 0
3 years ago
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