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Bess [88]
4 years ago
6

A beam of light strikes a mirror reflects off at the angle in which it hit the mirror. which term does the diagram below illustr

ate A. Rotation B. Reflection C.refraction D.revolution
Physics
1 answer:
zavuch27 [327]4 years ago
3 0

Answer:

B.) reflection

Explanation:

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2. Predict what will happen if the 80 kg adult was further from the pivot (more right) and explain your reasoning. 3. Predict wh
Alika [10]

Answer:

2) τ = F x  torque increases, 3) troque decreases,

4)  man approaches the pivot and the child must move away

5)  Σ τ = 0

Explanation:

2) when the man moves away from the pivot his torque increases significantly, since his distance increases

                 τ = F x

                 τ = m g x

therefore the system rotates faster

3) when the child approaches the pivot, his troque decreases, because the distance decreases

                 τ = f x

therefore the system must spin slower

4) If we place the man and the child on the side of a scale, the movement must be the man approaches the pivot and the child must move away, so that the torque is the same and the system can reach a balance

5) the rotational equilibrium expression

                 Σ τ = 0

is the one that describes the equilibrium of a system with several forces

8 0
3 years ago
What does it mean for PE to be dependent on the reference level?
Anastasy [175]

Answer:

The potential energy of an object is the energy possessed by the object due to its position in a gravitational field.

Mathematically, it is given by:

PE=mgh

where

m is the mass of the object

g is the acceleration due to gravity at the location of the object

h is the height of the object

As we can see, the potential energy depends on the height of the object, h.

However, this height is relative, since it can be measured using different reference levels.

Generally, the reference level is taken to be the ground; so for example, an object located at the top of a cliff 40 m above the ground, has

h = 40 m

But this value is of course relative, since we can also take the reference level to be the top of the cliff, so in that case, we would have

h = 0

3 0
3 years ago
Provident fund Rs. 100.000,
yulyashka [42]

Answer:

whatz dis 4

Explanation:

8 0
3 years ago
A 2200 kg car moving east at 10.3 m/s collides with a 3160 kg car moving east. The carsstick together and move east as a unit af
IgorLugansk [536]

Answer:

u = 1.77 m/s

Explanation:

Conservation of momentum

2250(10.3) + 3160u = (2250 + 3160)(5.32)

u = 1.77 m/s

8 0
3 years ago
Una fuerza F de 200 lb actúa a lo largo de AB, sobre la rampa mostrada. fuerza de F respecto del eje OC. Calcule el momento de f
ruslelena [56]

Answer:

Moc = -613.25 [lb*in]

Explanation:

Este problema se puede resolver mediante la mecánica vectorial, es decir se realizara un analisis de vectores.

Primero se calculara el momento de la fuerza F_AB con respecto al punto O, debemos recordar que el momento con respecto a un punto se define como el producto cruz de la distancia por la fuerza.

M_{o}=r_{A/O} * F_{AB} (producto cruz)

Necesitamos identificar los puntos:

O (0,0,0) [in]

A (12,0,0) [in]

B (0, 24,8) [in]

C (12,24,0) [in]

r_{A/O}=(12,0,0) - (0,0,0)\\r_{A/O} = 12 i + 0j+0k [in]\\AB = (0,24,8) - (12,0,0)\\AB = -12i+24j+8k [in]\\[LAB]=\frac{-12i+24j+8k}{\sqrt{(12)^{2} +(24)^{2} +(8)^{2} } }\\ LAB=-\frac{3}{7} i+\frac{6}{7}j+\frac{2}{7}k

El ultimo vector calculado corresponde al vector unitario (magnitud = 1) de AB. El vector fuerza corresponderá al producto del vector unitario por la magnitud de la fuerza = 200 [lb].

F_{AB}=-\frac{600}{7} i +\frac{1200}{7}j+\frac{400}{7} k [Lb]

De esta manera realizando el producto cruz tenemos

M_{O}=r_{A/O} * F_{AB}

M_{O}=0i-685.7j+2057.1k [Lb*in]

Para calcular el momento con respecto a la diagonal OC, necesitamos el vector unitario de esta diagonal.

OC = (12,24,0)-(0,0,0)\\OC= 12i+24j+0k[Lb]\\LOC = \frac{12i+24j+0k}{\sqrt{(12)^{2} +(24)^{2} +(0)^{2} } } \\LOC=\frac{12}{\sqrt{720}}i+\frac{24}{\sqrt{720}}j  +0k

El vector con respecto al eje OC, es igual al producto punto del momento en el punto O por el vector unitario LOC

M_{OC}=L_{OC}*M_{O}\\M_{OC}=(\frac{12}{\sqrt{720}}i +\frac{24}{\sqrt{720}} j+0k )* (0i-685.7j+2057.1k)\\M_{OC}= -613.32[Lb*in]

7 0
3 years ago
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