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marishachu [46]
3 years ago
10

Fg =G m1m2/r2 solver for G

Physics
1 answer:
Blababa [14]3 years ago
6 0

G = \frac{F_{g} r^{2}  }{m_{1} m_{2}  }

Explanation:

 Solving for G simply implies that we make G the subject of the formula:

  Given equation:

               F_{g} = G \frac{m_{1}  m_{2} }{ r^{2} }

 To make G the subject of this expression follow these steps:

            Multiply both sides of the equation by r^{2}

   

     F_{g} x r^{2} = G \frac{m_{1}  m_{2} }{ r^{2} } x r^{2}

 

      This gives:

                F_{g}  r^{2} = G m_{1}  m_{2}

     

    Multiply both sides by \frac{1}{m_{1} m_{2} }

  F_{g}  r^{2}  x   \frac{1}{m_{1} m_{2} } =  \frac{1}{m_{1} m_{2} } x G m_{1}  m_{2}

  Therefore:

                G = \frac{F_{g} r^{2}  }{m_{1} m_{2}  }

Learn more:

Solving formula brainly.com/question/2998489

#learnwithBrainly

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Explanation:

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Answer:

Explanation:

Weight of the ladder is 355N

WL = 355N

The weight of the ladder acts at center of the ladder I.e at 4m from the bottom

Weight of firefighters is 870N

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The fire fighter is at 6.3m from the bottom of the ladder.

N1 is the normal force exerted  by the wall

N2 is the normal force exerted  by the ground

Using Newton law

Check attachment

ΣFy = 0, since body is in equilibrium

N₂ - WL - Wf = 0

N₂ = WL + Wf

N₂ = 870 + 355

N₂ = 1225 N

This the normal force exerted by the ground on the wall.

Now to get N₁, let take moment about point A

So, before we take the moment we need to make sure that the forces are perpendicular to the plane(ladder), we need to resolve the weight of the ladder, firefighter and the normal of the wall to be perpendicular to the plane.

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Moment Is the produce of force and perpendicular distance.

M = F×r

So,

WL•Cos50 × 4 + Wf•Cos50 × 6.3 —N₁•Sin50 × 8 = 0

355•Cos50 × 4 + 870•Cos50 × 6.3 =

N₁•Sin50 × 8

1825.52 + 3523.12 = 6.13N₁

6.13N₁ = 5348.64

N₁ = 5348.64/6.13

N₁ = 872.54 N.

The normal force exerted by the wall is 872.54N

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