Answer:
First of all the formula is F= uR,( force= static friction× reaction)
mass= 5+25=30
F= 50
R= mg(30×10)=300
u= ?
F=UR
u= F/R
u= 50/300=0.17N
Calculate the pressure due to sea water as density*depth.
That is,
pressure = (1025 kg/m^3)*((9400 m)*(9.8 m/s^2) = 94423000 Pa = 94423 kPa
Atmospheric pressure is 101.3 kPa
Total pressure is 94423 + 101.3 = 94524 kPa (approx)
The area of the window is π(0.44 m)^2 = 0.6082 m^2
The force on the window is
(94524 kPa)*(0.6082 m^2) = 57489.7 kN = 57.5 MN approx
On driving your motorcycle in a circle of radius 75 m on wet pavement, the fastest you can go before you lose traction, assuming the coefficient of static friction is 0.20 is 147m/s
Friction helps to maintain the slipping of the vehicle on the road hence lays a very important role.
Maximum velocity of a road with friction is given by the formula,
v = μRg
where, v is the maximum velocity
μ is the coefficient of static friction
R is the radius of the circle road
g is the acceleration due to gravity
Given,
μ = 0.20
R = 75m
g = 9.8m/s²
On substituting the given values in the above formula,
v = 0.20× 75 ×9.8
v = 147m/s
So, the Maximum velocity of the wet road is 147m/s.
Learn more about Velocity here, brainly.com/question/18084516
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Answer:
just awnsered this one your awnser is the the second option
The concept of power is given by the relationship between intensity and area, that is to say that power is defined as
![P = A*I](https://tex.z-dn.net/?f=P%20%3D%20A%2AI)
Our values are given under the condition of,
![r_1 = 18m](https://tex.z-dn.net/?f=r_1%20%3D%2018m)
![r_2 = m](https://tex.z-dn.net/?f=r_2%20%3D%20m)
The power is proportional to the Area, and in turn, we know that the Area of a circle is the product between
times the radius squared, therefore the power is proportional to the radius squared.
![\text{Power} \propto r^2](https://tex.z-dn.net/?f=%5Ctext%7BPower%7D%20%5Cpropto%20r%5E2)
For both panels we would have to
![\frac{\text{Power by panel 1}}{\text{Power by panel 2}} = \frac{r_1^2}{r_2^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7BPower%20by%20panel%201%7D%7D%7B%5Ctext%7BPower%20by%20panel%202%7D%7D%20%3D%20%5Cfrac%7Br_1%5E2%7D%7Br_2%5E2%7D)
![\frac{P_1}{P_2} = (\frac{18}{6})^2](https://tex.z-dn.net/?f=%5Cfrac%7BP_1%7D%7BP_2%7D%20%3D%20%28%5Cfrac%7B18%7D%7B6%7D%29%5E2)
![\frac{P_1}{P_2} = 9](https://tex.z-dn.net/?f=%5Cfrac%7BP_1%7D%7BP_2%7D%20%3D%209)
Therefore the correct option is option C.9