Answer:
H = 1/2 g t^2 where t is time to fall a height H
H = 1/8 g T^2 where T is total time in air (2 t = T)
R = V T cos θ horizontal range
3/4 g T^2 = V T cos θ 6 H = R given in problem
cos θ = 3 g T / (4 V) (I)
Now t = V sin θ / g time for projectile to fall from max height
T = 2 V sin θ / g
T / V = 2 sin θ / g
cos θ = 3 g / 4 (T / V) from (I)
cos θ = 3 g / 4 * 2 sin V / g = 6 / 4 sin θ
tan θ = 2/3
θ = 33.7 deg
As a check- let V = 100 m/s
Vx = 100 cos 33.7 = 83,2
Vy = 100 sin 33,7 = 55.5
T = 2 * 55.5 / 9.8 = 11.3 sec
H = 1/2 * 9.8 * (11.3 / 2)^2 = 156
R = 83.2 * 11.3 = 932
R / H = 932 / 156 = 5.97 6 within rounding
Because the momentum would still be applied to the orange if the tray stopped moving
<span>The correct answer is letter B. less than the angle of refraction. </span>When a beam of light passes at an oblique angle into a material of lower optical density, the angle of incidence is <span>less than the angle of refraction. The reason for that because the beam of light passes through an oblique angle.</span>
Balanced Forces are different from Unbalanced Forces because Balanced Forces are two forces acting in opposite directions of an object, and equal in size.On the other hand unbalanced forces are forces that cause a change in the motion of an object.
This impacts motion because when balance forces enter,... the object either stops (Stays at rest or moves at the same speed and direction) Unbalanced Forces causes an object to move faster/slower (might change the direction),.. due to one side having more force than the other.
~Revilla03
