Si units are the modern form of the

A 3.50 kg block of lead at 14.4°C comes in contact with a block of copper at 88.4°C. They come to equilibrium at 55.9°C. What wa

satela [25.4K]

Answer:

1.48 kg

Explanation:

The conservation of energy states that energy cannot be created or destroyed but can be converted from one form to another. Hence, in this case, energy lost by the copper should equal to the energy gained by the lead. Hence,

Energy Lost by Copper = Energy Gained by Lead

mcT = mcT (Bolded is for copper, italicised is for lead)

m(387)(88.4 - 55.9) = (3.50)(128)(55.9 - 14.4)

12577.5m = 18592

m = 1.48 kg (3 sf)

(Note: Thermal energy can be calculated using Q = mcT where m is the mass, c is the specific heat capacity and T is the change in temperature)

8 0

4 years ago

Read 2 more answers

Much of the bedrock in Virginia’s Piedmont region, originally formed by cooled magma, has re-crystallized under a great deal of

3241004551 [841]

A) gneiss

Explanation:

The likely rock that would be found here is gneiss.

A rock type that forms under a great deal of temperature and pressure is a metamorphic rock.

Such rocks would have their minerals crystallized when subjected to these extreme conditions.

Metamorphic rocks are changed rocks that are formed when minerals in rocks are subjected to extreme pressure and temperature before they start melting.
These rock type can form from either sedimentary or igneous rocks. In fact a metamorphic rock can also change into another one.
Examples of metamorphic rocks are gneiss, schist, hornfels, marble etc.

Halite, limestone and sandstone are examples of sedimentary rocks that forms by the accumulation of sediments or precipitation of ions form solutions.

learn more:

Metamorphic change brainly.com/question/869769

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6 0

4 years ago

What are the four major tasks of the digestive system?

galben [10]

Answer:

Option A

The four major tasks of the digestive system are - Ingestion, Digestion, Absorption, Elimination

Explanation:

A digestive system has primarily four main functions

a) Motility - In this the food is ingested through opening in the form of mouth and then it starts moving from the mouth via esophagus to the stomach

b) Digestion - In the stomach, the food gets digestion and then it is passed on to the intestine

c) Absorption - In the small intestine essential nutrients and water is absorbed

b) Secretion - The waste remaining after intestine digestion is passed on to the rectum for secretion

Hence, option A is correct

5 0

3 years ago

A pitcher claims he can throw a 0.146-kg baseball with as much momentum as a 2.70-g bullet moving with a speed of 1.50 ✕ 103 m/s

Nataly_w [17]

(a) The pitcher must throw the ball at 27.7 m/s

The momentum of an object is given by:

$p=mv$

where

m is the mass of the object

v is the object's velocity

Let's calculate the momentum of the bullet, which has a mass of

m = 2.70 g = 0.0027 kg

and a velocity of

$v=1.50\cdot 10^3 m/s$

Its momentum is:

$p=mv=(0.0027 kg)(1.50\cdot 10^{3} m/s)=4.05 kg m/s$

The pitcher must throw the baseball with this same momentum. The mass of the ball is

m = 0.146 kg

So the velocity of the ball must be

$v=\frac{p}{m}=\frac{4.05 kg m/s}{0.146 kg}=27.7 m/s$

So, the pitcher must throw the ball at 27.7 m/s.

(b) a. The bullet has greater kinetic energy

The kinetic energy of an object is given by

$K=\frac{1}{2}mv^2$

where m is the mass of the object and v is its speed.

For the bullet, we have:

$K=\frac{1}{2}(0.0027 kg)(1.50\cdot 10^3 m/s)^2=3037.5 J$

For the ball:

$K=\frac{1}{2}(0.146 kg)(27.7 m/s)^2=56.0 J$

So, the bullet has greater kinetic energy.

6 0

3 years ago

A flux density of 1.2Wb/m^2 is required in the 1 mm air gap of an electromagnet having an iron path of length 1.5 m. Calculate t

Mandarinka [93]

Answer:

The mmf required is $1.125$ × $10^{-3}$ A

Explanation:

The Magnetomotive force (mmf) is given by the formula below

$F_{M} = Hl\\$

where $F_{M}$ is the Magnetomotive force (mmf)

$H$ is the Magnetic field strength

$l$ is the magnetic length

The magnetic permeability μ is given by

μ = $B / H$

Where $B$ is the Magnetic flux density

and $H$ is the Magnetic field strength

From the question,

$B$ = 1.2Wb/m^2

μ = 1600m

From μ = $B / H$

∴ $H = B/$ μ

$H = 1.2 / 1600\\$

$H = 7.5$ × $10^{-4}$ A/m

Now, for the Magnetomotive force (mmf)

$F_{M} = Hl\\$

From the question

$l$ = 1.5 m

∴ $F_{M} = 7.5$ × $10^{-4}$ × $1.5$

$F_{M} = 1.125$ × $10^{-3} A$

Hence, The mmf required is $1.125$ × $10^{-3}$ A

3 0

3 years ago