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sweet [91]
3 years ago
15

The scientist who discovered the laws of motion was _____.

Physics
1 answer:
stiks02 [169]3 years ago
8 0

Sir Isaac Newton discovered and described the laws of motion in his book Principia Mathematica published on July 5th, 1687.

D. Isaac Newton

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Why is fair play essential in sports?​
Dmitry [639]

Answer: it teaches people tolerance and respect for others.

Explanation:

5 0
2 years ago
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Light of a given wavelength is used to illuminate the surfacce of a metal, however, no photoelectrons are emitted. In order to c
Jlenok [28]

Answer:

B. use light of a shorter wavelength.

Explanation:

We know that

E= \frac{hc}{\lambda}

h= plank's constant

c= speed of light

λ= wavelength of the incident light

so, in order to have sufficient energy for for the emission of electron, the incident's radiation must have λ small enough.

B. use light of a shorter wavelength.

6 0
3 years ago
What is the velocity of an object with a kinetic energy of 800 J and a mass of 12 kg?
Elis [28]

K.E = 1/2 mv²

800 = 1/2 ×12 ×v²

800 =  6 v²

800 / 6  =  v²

=   133.4    =v²

√133.4  =   √v²

11.5   =  v²

I hope this answer is correct.

3 0
3 years ago
The amount of matter in an object is called its
Serga [27]
The amount of matter in an object is called its, mass. How much the mass weights would be referred to as weight
7 0
3 years ago
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The 45-g arrow is launched so that it hits and embeds in a 1.40 kg block. The block hangs from strings. After the arrow joins th
worty [1.4K]

Question: How fast was the arrow moving before it joined the block?

Answer:

The arrow was moving at 15.9 m/s.

Explanation:

The law of conservation of energy says that the kinetic energy of the arrow must be converted into the potential energy of the block and arrow after it they join:

\dfrac{1}{2}m_av^2 = (m_b+m_a)\Delta Hg

where m_a is the mass of the arrow, m_b is the mass of the block, \Delta H of the change in height of the block after the collision, and v is the velocity of the arrow before it hit the block.

Solving for the velocity v, we get:

$v = \sqrt{\frac{2(m_b+m_a)\Delta Hg}{m_a} } $

and we put in the numerical values

m_a = 0.045kg,

m_b = 1.40kg,

\Delta H = 0.4m,

g= 9.8m/s^2

and simplify to get:

\boxed{ v= 15.9m/s}

The arrow was moving at 15.9 m/s

6 0
3 years ago
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