Answer:
Explanation:
destroyerplayz20062
13 hours ago
Chemistry
High School
Predict the Eº values for all (6) combinations of the following: Cu(s) and Cu(NO3)2(aq) Fe(s) and Fe(NO3)3(aq) Zn(s) and Zn(NO3)2(aq) Pb(s) and Pb(NO3)2(aq)
destroyerplayz20062
13 hours ago
Chemistry
High School
Predict the Eº values for all (6) combinations of the following: Cu(s) and Cu(NO3)2(aq) Fe(s) and Fe(NO3)3(aq) Zn(s) and Zn(NO3)2(aq) Pb(s) and Pb(NO3)2(aq)
destroyerplayz20062
13 hours ago
Chemistry
High School
Predict the Eº values for all (6) combinations of the following: Cu(s) and Cu(NO3)2(aq) Fe(s) and Fe(NO3)3(aq) Zn(s) and Zn(NO3)2(aq) Pb(s) and Pb(NO3)2(aq)
destroyerplayz20062
13 hours ago
Chemistry
High School
Predict the Eº values for all (6) combinations of the following: Cu(s) and Cu(NO3)2(aq) Fe(s) and Fe(NO3)3(aq) Zn(s) and Zn(NO3)2(aq) Pb(s) and Pb(NO3)2(aq)
Answer:
It's called carbon dioxide.
Explanation:
consists of 1 carbon atom bonding with two oxygen atoms.
2.999 is the amount of moles
Answer: 1.06 kg
Explanation:
Density is defined as the mass contained per unit volume.
Given :
Density of mercury = 
volume of cylinder = volume of mercury = 
where r = radius of cylinder = 
h= height = 25.0 cm
Putting in the values we get:
volume of mercury =
(1kg=1000g)
Thus mass of mercury required to fill a hollow cylinder having an inner diameter of 2.00 cm to a height of 25.0 cm is 1.06 kg.
Answer:
Possible lowest volume = 0.19 cm
Possible highest volume = 0.21 cm
Explanation:
Given Data
uncertainty = 0.01 cm
total volume = 0.20 cm
Possible lowest volume = ?
Possible highest volume = ?
Solution:
Possible lowest volume = total volume - uncertainty
Possible lowest volume = 0.20 cm - 0.01 cm
Possible lowest volume = 0.19 cm
Possible highest volume = total volume + uncertainty
Possible highest volume = 0.20 cm - 0.01 cm
Possible highest volume = 0.21 cm
