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inessss [21]
3 years ago
7

Explain why the windows at the front of airlines ar3 much bigger​

Chemistry
2 answers:
Leviafan [203]3 years ago
7 0

Answer:

La mea vola weon

Explanation: Tu mai es zoerrra

MariettaO [177]3 years ago
7 0
Can u help no one is helping me
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Predict the Eº values for all (6) combinations of the following: Cu(s) and Cu(NO3)2(aq) Fe(s) and Fe(NO3)3(aq) Zn(s) and Zn(NO3)
Butoxors [25]

Answer:

Explanation:

destroyerplayz20062

13 hours ago

Chemistry

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Predict the Eº values for all (6) combinations of the following: Cu(s) and Cu(NO3)2(aq) Fe(s) and Fe(NO3)3(aq) Zn(s) and Zn(NO3)2(aq) Pb(s) and Pb(NO3)2(aq)​

destroyerplayz20062

13 hours ago

Chemistry

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Predict the Eº values for all (6) combinations of the following: Cu(s) and Cu(NO3)2(aq) Fe(s) and Fe(NO3)3(aq) Zn(s) and Zn(NO3)2(aq) Pb(s) and Pb(NO3)2(aq)​

destroyerplayz20062

13 hours ago

Chemistry

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Predict the Eº values for all (6) combinations of the following: Cu(s) and Cu(NO3)2(aq) Fe(s) and Fe(NO3)3(aq) Zn(s) and Zn(NO3)2(aq) Pb(s) and Pb(NO3)2(aq)​

destroyerplayz20062

13 hours ago

Chemistry

High School

Predict the Eº values for all (6) combinations of the following: Cu(s) and Cu(NO3)2(aq) Fe(s) and Fe(NO3)3(aq) Zn(s) and Zn(NO3)2(aq) Pb(s) and Pb(NO3)2(aq)​

6 0
2 years ago
Use the drop-down menu to complete the sentence.
Paha777 [63]

Answer:

It's called carbon dioxide.

Explanation:

CO_{2} consists of 1 carbon atom bonding with two oxygen atoms.

5 0
3 years ago
Read 2 more answers
How many moles are 1.806 x 10^24 atoms?
djyliett [7]
2.999  is the amount of moles
4 0
3 years ago
The density of liquid mercury is 13.5 g/cm^3. What mass of mercury (in kg) is required to fill a hollow cylinder having an inner
olya-2409 [2.1K]

Answer: 1.06 kg

Explanation:

Density is defined as the mass contained per unit volume.

Density=\frac{mass}{Volume}

Given :

Density of mercury = 13.5g/cm^3

volume of cylinder  = volume of mercury = \pir^2h

where r = radius of cylinder = \frac{diameter}{2}=\frac{2cm}{2}=1cm

h= height = 25.0 cm

Putting in the values we get:

volume of mercury =3.14\times 1^2\times 25=78.5cm^3

mass=density\times volume=13.5g/cm^3\times 78.5cm^3=1059.75g=1.06kg      (1kg=1000g)

Thus mass of mercury required to fill a hollow cylinder having an inner diameter of 2.00 cm to a height of 25.0 cm is 1.06 kg.

4 0
3 years ago
a volumetric pipette haas an uncertainty of 0.01 cm what are the lowest and highest possible volumes for a measurement of 0.20cm
Vanyuwa [196]

Answer:

Possible lowest volume = 0.19 cm

Possible highest volume = 0.21 cm

Explanation:

Given Data

uncertainty  =  0.01 cm

total volume = 0.20 cm

Possible lowest volume = ?

Possible highest volume =  ?

Solution:

Possible lowest volume = total volume - uncertainty

Possible lowest volume = 0.20 cm - 0.01 cm

Possible lowest volume = 0.19 cm

Possible highest volume = total volume + uncertainty

Possible highest volume = 0.20 cm - 0.01 cm

Possible highest volume = 0.21 cm

5 0
3 years ago
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