To do that, we would need to know what is "described above".
Answer:
here's an explanation but not the answer
please kindly send No or Yes understand.
Explanation:
A 10-N force is applied to push a block across a friction free surface for a displacement of 5.0 m to the right.
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A 10-N frictional force slows a moving block to a stop after a displacement of 5.0 m to the right.
There’s no picture and what’s the length?
Answer:
Solid sphere will reach first
Explanation:
When an object is released from the top of inclined plane
Then in that case we can use energy conservation to find the final speed at the bottom of the inclined plane
initial gravitational potential energy = final total kinetic energy

now we have

here k = radius of gyration of object
also for pure rolling we have

so now we will have



so we will say that more the value of radius of gyration then less velocity of the object at the bottom
So it has less acceleration while moving on inclined plane for object which has more value of k
So it will take more time for the object to reach the bottom which will have more radius of gyration
Now we know that for hoop

k = R
For spherical shell


For solid sphere


So maximum value of radius of gyration is for hoop and minimum value is for solid sphere
so solid sphere will reach the bottom at first
Answer:
Centripetal force = 11789 N
Explanation:
Recall that the centripetal acceleration is defined as the square of the tangential velocity divided by the radius of the circular rotation. Then for our case, the centripetal acceleration is:
ac = (11.8 m/s)^2 / 15 m = 9.28266 m/s^2
then, such acceleration on a mass of 1270 kg will render a centripetal force of:
Fc = m * ac = 1270 * 9.28266 N = 11789 N