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agasfer [191]
2 years ago
8

The frequency of a certain sound is 440 Mz. What is the wavelength of this sound when the temperature of the air is (a) 20°C; (b

) 30°C
Physics
1 answer:
Serggg [28]2 years ago
3 0

Answer:

Explanation:

We know the frequency and the velocity, both of which have good units. All we have to do is rearrange the equation and solve for

λ

:

λ

=

v

f

Let's plug in our given values and see what we get!

λ

=

340

m

s

440

s

−

1

λ

=

0.773

m

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kakasveta [241]
To do that, we would need to know what is "described above".
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allochka39001 [22]

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Explanation:

A 10-N force is applied to push a block across a friction free surface for a displacement of 5.0 m to the right.

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3 years ago
A hoop, a solid cylinder, a spherical shell, and a solid sphere are placed at rest at the top of an inclined plane. All the obje
iogann1982 [59]

Answer:

Solid sphere will reach first

Explanation:

When an object is released from the top of inclined plane

Then in that case we can use energy conservation to find the final speed at the bottom of the inclined plane

initial gravitational potential energy = final total kinetic energy

mgh = \frac{1}{2}mv^2 + \frac{1}{2}I\omega^2

now we have

I = mk^2

here k = radius of gyration of object

also for pure rolling we have

v = R\omega

so now we will have

mgh = \frac{1}{2}mv^2 + \frac{1}{2}(mk^2)(\frac{v^2}{R^2})

mgh = \frac{1}{2}mv^2(1 + \frac{k^2}{R^2})

v^2 = \frac{2gh}{1 + \frac{k^2}{R^2}}

so we will say that more the value of radius of gyration then less velocity of the object at the bottom

So it has less acceleration while moving on inclined plane for object which has more value of k

So it will take more time for the object to reach the bottom which will have more radius of gyration

Now we know that for hoop

mk^2 = mR^2

k = R

For spherical shell

mk^2 = \frac{2}{3}mR^2

k = \sqrt{\frac{2}{3}} R

For solid sphere

mk^2 = \frac{2}{5}mR^2

k = \sqrt{\frac{2}{5}} R

So maximum value of radius of gyration is for hoop and minimum value is for solid sphere

so solid sphere will reach the bottom at first

7 0
3 years ago
A car of mass 1270 kg makes a 15.0 m radius turn at 11.8 m/s on flat ground. How much centripetal force acts on it?
svp [43]

Answer:

Centripetal force = 11789 N

Explanation:

Recall that the centripetal acceleration is defined as the square of the tangential velocity divided by the radius of the circular rotation. Then for our case, the centripetal acceleration is:

ac = (11.8 m/s)^2 / 15 m = 9.28266 m/s^2

then, such acceleration on a mass of 1270 kg will render a centripetal force of:

Fc = m * ac = 1270 * 9.28266 N = 11789 N

3 0
3 years ago
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