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zysi [14]
3 years ago
11

For stars to form, the temperature of the hydrogen in a nebula must be more than 14 million Kelvin. How did gravitational attrac

tion help achieve these high temperatures?
Physics
2 answers:
tensa zangetsu [6.8K]3 years ago
7 0

Answer:

the short version is density

Explanation:

so the outer part of the nebula is cold and dark 10-20k but at this temutre the gas clumps together heating it up more mass = more gravity = more heat and the gravity will pull more mass that will give the proto star the spherical shape we all know and love

grandymaker [24]3 years ago
5 0

Answer:

Gravitational attraction caused the volume of the nebula to decrease, which raised the particle motion and temperature at the center of the nebula to the necessary 14 million Kelvin.

Explanation:

Plato/edmentum sample answer

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Which of the following is the correct equation we get
UkoKoshka [18]

Answer:

\frac{a}{b}=c which agrees with the third answer in your list of answer options

Explanation:

Start with:

a=b\,*\,c

divide both sides by b to isolate c on the right:

\frac{a}{b} =\frac{b\,*\,c}{b} \\\frac{a}{b} =c

6 0
3 years ago
Savannah drove 716 miles on Monday. She drove another 572 miles on Tuesday. About how many miles did she drive
Korolek [52]

Explanation:

We have,

Savannah drove 716 miles on Monday and She drove another 572 miles on Tuesday.

It is required to find the total distance covered by her altogether. It is equal to the sum of distance covered on Monday and distance covered on Tuesday. So,

d = 716 miles + 572 miles

d = 1288 miles

So, she drive 1288 miles altogether.

5 0
4 years ago
Person 1 moves an object 10 meters and exerts a force of 50N in 5 seconds. Person 2 moves an object 10 meters and exerts a force
mel-nik [20]

Answer:

Explanation:

Work is a force time the distance moved in the direction of that force, time is not a variable. Provided that the 50 N forces were applied in the same direction, the work done is identical. Assuming both applied force and direction of motion are horizontal W = Fd = 50(10) = 500J.

If the reason that one was slower is because the  second person applied his force at an angle, let's say 60° below the horizontal, then the work done by the second person is 50cos60(10) = 250 J

Time IS a consideration for Power, the RATE of doing work. Provided the force and motion are horizontal, the first person applied twice as much Power as the second person doing an identical amount of work in half the time.

7 0
3 years ago
Three crates with various contents are pulled by a force F pull = 3615 N across a horizontal, frictionless roller‑conveyor syste
Dmitry_Shevchenko [17]

Answer:

m1=914.9kg

m2=604.9kg

m3=864.75kg

Explanation

I think we are suppose to find the mass of the crate.

The effective force that moves the body in positive x direction is 3615N

ΣFx = Σma

Then Fx=3615N

Then the masses be m1, m2 and m3

Then,

ΣF = Σ(ma)

3615=(m1+m2+m3)a

Given that a=1.516

The masses are

m1+m2+m3=, 2384.56. Equation 1

Between mass 1 and mass 2 is, F12=1387.

The effective force that pull mass 1 is 1387.

F12=m1 ×a

Therefore,

m1=F12/a

m1=1387/1.516

m1=914.9kg.

The effective force that pulls crate 1 and crate 2 is F23

F23=(m1+m2)a

Therefore

2304=(m1+m2)a

Therefore, since a=1.516

m1+m2=2304/1.516

m1+m2=1519.8kg

Since m1=914.9kg

So, m2=1519.8-m1

m2=1519.8-914.9

m2=604.9kg

Also from equation 1

m1+m2+m3=2384.56

Since m1=914.9kg and m2=604.9kg

Then, m3=2384.56-604.9-914.9

m3=864.75kg

3 0
3 years ago
The liquid in the cup is brown" is an example of an ..............
erastova [34]
Eaither D or A bit I am leaning more towards D
3 0
3 years ago
Read 2 more answers
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