5 g of potassium oxalate react to produce 0.03 moles of calcium oxalate.
Calcium oxalate (CaC₂O₄) is obtained by the reaction of 5 g of potassium oxalate (K₂C₂O₄).
We can calculate the moles of CaC₂O₄ obtained considering the following relationships.
- The molar mass of K₂C₂O₄ is 184.24 g/mol.
- The mole ratio of K₂C₂O₄ to CaC₂O₄ is 2:1.

5 g of potassium oxalate react to produce 0.03 moles of calcium oxalate.
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Answer:
Long term condition of the atmosphere
Explanation:
I think this is right.
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Given:
The overall average speed = 25 cm/s.
The overall average speed increased by 10%.
To find:
The new overall average speed.
Solution:
We have,
Overall average speed = 25 cm/s.
The overall average speed increased by 10%. So, the new average speed is
New overall average speed = Initial average speed + 10% of initial overall average speed



Therefore, the new overall average speed is 27.5 cm/s.
Answer:False
Explanation:
Kinda of a opinionated question, but unless you call -12 C warm then the answer is False