The amount, in mL, of the concentrated acid required, would be 1.1875 mL
<h3>Dilution</h3>
From the dilution equation:
m1v1=m2v2 where m1 and m2 = molarity before and after dilution, and v1 and v2 = volume before and after dilution.
m2 = 0.285M, m1 = 12.0M v2 = 50.0 mL
v1 = m2v2/m1 = 0.285x50/12 = 1.1875 mL
Thus, 1.1875 mL of the acid would be taken and diluted with water up to the 50 mL mark.
More on dilution can be found here: brainly.com/question/13949222
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Take the 72 g and divid it by 6 which would equal 12 g each
3. B
4. A
5.A
6. A (i think)
Hope this helps
Answer:
¾ litters of water was consumed
2.24 litters = 1 mole of water
Therefore ¾÷2.24 moles was consumed
0.33 moles
Answer:
An oxidising agent oxidises something else. Oxidation is loss of electrons (OIL RIG). That means that an oxidising agent takes electrons from that other substance.
Explanation:
