How many atoms of chromium are in 0.86 mol of potassium chromate (K2CrO4)?

Chemistry

1 answer:

9966 [12]3 years ago

3 0

<h2>Answer:</h2>

Atoms of Cr in 0.86 mol of K2CrO4 = 0.86 × 6.02*10^23 = 5.177 * 10^23 atoms.

<h3>Explanation:</h3>

One mol of K2CrO4 contains 6.02*10^23 molecules of K2CrO4.
One K2CrO4 contains 1 atom of Cr.
So 0.86 mol of K2CrO4 contain 0.86 * 6.02*10^23.
Which is equal to 5.177 * 10^23 atoms.

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