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sveta [45]
3 years ago
15

How many atoms of chromium are in 0.86 mol of potassium chromate (K2CrO4)?

Chemistry
1 answer:
9966 [12]3 years ago
3 0
<h2>Answer:</h2>

Atoms of Cr in 0.86 mol of K2CrO4 = 0.86 × 6.02*10^23 = 5.177 * 10^23 atoms.

<h3>Explanation:</h3>
  • One mol of K2CrO4 contains 6.02*10^23 molecules of K2CrO4.
  • One K2CrO4  contains 1 atom of Cr.
  • So 0.86 mol of K2CrO4 contain 0.86 * 6.02*10^23.
  • Which is equal to  5.177 * 10^23 atoms.

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