<span>It relates the </span>measured<span> cell </span>potential<span> to the reaction quotient and allows the ... Substituting these expressions into Equation 20.6.</span>1<span>, we obtain ... the </span>standard<span> cell </span>potential<span> (E° cell), and the </span>reactant<span> and product concentrations at ... 0.013 </span>M, [Ce3+<span>] = 0.60 </span>M, [Cl−<span>] = 0.0030 </span>M, PC<span>l2 = 1.0 atm, and T = </span>25°C<span>.</span>
Answer:
26.25 mL
Explanation:
This is a dilution problem. First, let us calculate the volume of final solution needed:
The dog weighs 50 pounds and the sedative is administered at 0/7 ml per pound. Hence:
50 x 0.7 = 35 mL
A total volume of 35 mL, 2.5% solution of the sedative will be needed.
But 10% solution is available. There needs to be a dilution with saline water, but what volume of the 10% solution would be diluted?
initial volume = ?
final volume = 35 mL
initial concentration = 10%
final concentration = 2.5%
Using dilution equation:
initial concentration x initial volume = final concentration x final volume
initial volume = ![\frac{final concentration*final volume}{initial concentration}](https://tex.z-dn.net/?f=%5Cfrac%7Bfinal%20concentration%2Afinal%20volume%7D%7Binitial%20concentration%7D)
= 2.5 x 35/10 = 8.75 mL
Hence, 8.75 mL of the 10% pre-mixed sedative will be required.
But 35 mL is needed? The 8.75 mL is marked up to 35 mL with saline water.
35 - 8.75 = 26.25 mL
<em>Therefore, 26.25 mL of saline water will be added to 8.75 mL of the 10% pre-mixed sedative to give 2.5%, 35 mL needed for the dog.</em>
[H+][OH-]=10-¹⁴
We are using this formula because we need to find the H+
substitute the value given for hydronium ion for OH-
[H+][4.19×10⁵]=10-¹⁴
[H+]=10-¹⁴÷4.19×10⁵
[H+]=2.387×10-¹⁹
Then the pH of the solution will be
pH= –log¹⁰ [H+]
pH = –log¹⁰ [2.387×10-¹⁹]
pH= –log¹⁰2.387+19log¹⁰
= –0.378+19
pH =18.622
A. It’s known as the “universal solvent”
Staying in the sun too long causes skin burn and looking at the sun damages your eyes as well so it's C