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3 years ago

Percent composition H2S2O8

Chemistry

1 answer:

AleksAgata [21]3 years ago

8 0

Answer:194.1411 g/mol

Explanation:

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3. Are quartz and coal minerals or only naturally occurring substances?

klasskru [66]

Answer:

minerals

Explanation:

coal is made from decomposing matter

6 0

3 years ago

How to calculate the number of moles

babunello [35]

Answer:

1. The formula for the number of moles formula is expressed as.

2. Given.

3. Number of moles formula is.

4. Number of moles = Mass of substance / Mass of one mole.

5. Number of moles = 95 / 86.94.

6 0

3 years ago

In a double-blind test, the non-control group receives a

Aleksandr [31]

Answer:

Hi There! I'm new so I hope I get This Right! ^^

Explanation:

double blind test. the control group receives a placebo. Why is a placebo used in a double-blind test? so that the effects on people in two different groups can be compared.

happy To Help! ^^

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3 years ago

How many atoms of oxygen (O) are represented in the chemical formula shown below?

Bad White [126]

One atom of oxygen .

7 0

3 years ago

(6 points) Alice owns 20 grams of a radioactive isotope that has a half-life of ln(4) years. (a) Find an equation for the mass m

Cloud [144]

Answer: The equation to calculate the mass of remaining isotope is $[A]=\frac{20}{10^{-0.217t}}$

Explanation:

The equation used to calculate rate constant from given half life for first order kinetics:

$t_{1/2}=\frac{0.693}{k}$

where,

$t_{1/2}$ = half life of the reaction = $\ln 4=1.386yrs$

Putting values in above equation, we get:

$k=\frac{0.693}{1.386yrs}=0.5yrs^{-1}$

Rate law expression for first order kinetics is given by the equation:

$k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}$

where,

k = rate constant = $0.5yr^{-1}$

t = time taken for decay process

$[A_o]$ = initial amount of the sample = 20 grams

[A] = amount left after decay process = ? grams

Putting values in above equation, we get:

$0.5=\frac{2.303}{t}\log\frac{20}{[A]}$

$[A]=\frac{20}{10^{-0.217t}}$

Hence, the equation to calculate the mass of remaining isotope is $[A]=\frac{20}{10^{-0.217t}}$

6 0

3 years ago