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slega [8]
3 years ago
8

Percent composition H2S2O8

Chemistry
1 answer:
AleksAgata [21]3 years ago
8 0

Answer:194.1411 g/mol

Explanation:

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What type of representative particle does KClO3 have?
bogdanovich [222]

Answer:

formula units

Explanation:

$KClO_3$  is  potassium chlorate. It is an ionic compound containing potassium, chlorine and oxygen. The ion in potassium chlorate are held together by the ionic bonds in the lattice structure.

A representative particle may be defined as the smallest unit for which the substance exists in its natural form. For most of the elements, atom is the representative particle. Molecule is the representative particle for diatoms and molecular compounds. But for ionic compounds such as  $KClO_3$ , NaCl, etc. . the representative particle is its formula units.

6 0
3 years ago
Problem: Janna, a student of a chemistry class, told her friend that she learnt in class that bottled water is not pure. Kim, he
Ghella [55]

Answer:

The bottle is labeled pure so it probably is pure.

Explanation:

4 0
3 years ago
Choose the TRUE statement. A. Laurasia broke up to form Pangaea and Gondwanaland. B. Pangaea broke up to form Laurasia and Gondw
Amanda [17]
B is the correct answer since both Gondwanaland and Laurasia both technically came after pangaea
8 0
3 years ago
Read 2 more answers
Nitrogen (N2) enters a well-insulated diffuser operating at steady state at 0.656 bar, 300 K with a velocity of 282 m/s. The inl
Tasya [4]

Answer:

  1. The exit temperature of the Nitrogen would be 331.4 K.
  2. The area at the exit of the diffuser would be 7*10^{-3} m^2.
  3. The rate of entropy production would be 0.

Explanation:

  1. First it is assumed that the diffuser works as a isentropic device. A isentropic device is such that the entropy at the inlet is equal that the entropy T the exit.
  2. It will be used the subscript <em>1 for the</em> <em>inlet conditions of the nitrogen</em>, and the subscript <em>2 for the exit conditions of the nitrogen</em>.
  3. It will be called: <em>v</em> the velocity of the nitrogen stream, <em>T</em> the nitrogen temperature, <em>V</em> the volumetric flow of the specific stream, <em>A</em> the area at the inlet or exit of the diffuser and, <em>P</em> the pressure of the nitrogen flow.
  4. It is known that <em>for a fluid flowing, its volumetric flow is obtain as:</em> V=v*A,
  5. Then for the inlet of the diffuser: V_1=v_1*A_1=282\frac{m}{s}*4.8*10^{-3}m^2=1.35\frac{m^3}{s}
  6. For an ideal gas working in an isentropic process, it follows that: \frac{T_{2} }{T_1}=(\frac{P_2}{P_1})^k where each variable is defined according with what was presented in step 2 and 3, and <em>k </em>is the heat values relationship, 1.4 for nitrogen.
  7. Then <em>solving</em> for T_2, the temperature of the nitrogen at the exit conditions: T_2=T_1(\frac{P_2}{P_1})^k then, T_2=300 K (\frac{0.9 bar}{0.656 bar})^{(\frac{1.4-1}{1.4})}=331.4 K
  8. Also, for an ideal gas working in an isentropic process, it follows that:  \frac{P_2}{P_1}= (\frac{V_1}{V_2})^k, where each variable is defined according with what was presented in step 2 and 3, and <em>k</em> is the heat values relationship, 1.4 for nitrogen.
  9. Then <em>solving</em> for V_2 the volumetric flow at the exit of the diffuser: V_2=V_1*\frac{1}{\sqrt[k]{\frac{P_2}{P_1}}}=\frac{1.35\frac{m^3}{s}}{\sqrt[1.4]{\frac{0.9bar}{0.656bar} }}=1.080\frac{m^3}{s}.
  10. Knowing that V_2=1.080\frac{m^3}{s}, it is possible to calculate the area at the exit of the diffuser, using the relationship presented in step 4, and solving for the required parameter: A_2=\frac{V_2}{v_2}=\frac{1.08\frac{m^3}{s} }{140\frac{m}{s}}=7.71*10^{-3}m^2.
  11. <em>To determine the rate of entropy production in the diffuser,</em> it is required to do a second law balance (entropy balance) in the control volume of the device. This balance is: S_1+S_{gen}-S_2=\Delta S_{system}, where: S_1 and S_2 are the entropy of the stream entering and leaving the control volume respectively, S_{gen} is the rate of entropy production and, \Delta S_{system} is the change of entropy of the system.
  12. If the diffuser is operating at stable state is assumed then \Delta S_{system}=0. Applying the entropy balance and solving the rate of entropy generation: S_{gen}=S_2-S_1.
  13. Finally, it was assume that the process is isentropic, it is: S_1=S_2, then S_{gen}=0.
6 0
3 years ago
When solutions of silver nitrate and sodium chloride are mixed, a precipitation reaction occurs. What mass of precipitate can be
Bas_tet [7]

Explanation:

The given precipitation reaction will be as follows.

        AgNO_{3}(aq) + NaCl(aq) \rightarrow AgCl(s) + NaNO_{3}(aq)

Here, AgCl is the precipitate which is formed.

It is known that molarity is the number of moles present in a liter of solution.

Mathematically,       Molarity = \frac{\text{no. of moles}}{\text{volume in liter}}

It is given that volume is 1.14 L and molarity is 0.269 M. Therefore, calculate number of moles as follows.

                    Molarity = \frac{\text{no. of moles}}{\text{volume in liter}}

                     0.269 M = \frac{\text{no. of moles}}{1.14 L}

                    no. of moles = 0.306 mol

As molar mass of AgCl is 143.32 g/mol. Also, relation between number of moles and mass is as follows.

               No. of moles = \frac{mass}{\text{molar mass}}

                   0.307 mol = \frac{mass}{143.32 g/mol}

                           mass = 43.99 g

Thus, we can conclude that mass of precipitate produced is 43.99 g.

                 

8 0
3 years ago
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